To best emphasize the number of defects. Manager should use graph 3 (refer the image shown):
If we talk about graph 1, it can also be used but usually we put the time line on the horizontal axis, for the convenience and the quantity to be measured on the y-axis. In the graph 1, the time is placed on the vertical axis (x-axis) so it would not be a good pick for the manager.
Same is the case with graph 2 again we have time on the vertical axis. So it is not a good idea to with graph 2.
Graph 3 could be the best to emphasize the number of defects because first of all time is placed on the horizontal axis and the quantity to be shown is on the vertical axis. Secondly, the range of the vertical axis is less so it is easy to observe the data set on the graph quite distinctively. Therefore, graph 3 is the best pick.
Graph 4 is placed correctly in terms of vertical and horizontal axes but the range of vertical axis is quite high due to which the dispersion or the display of the data is quite compressed and it gets hard to visualize.
Answer:
5 days
Step-by-step explanation:
Sohan can do the whole thing in 10 days
he worked 5 days so he did half
and Mohan did the other half in 5 days
so their speeds are same
so if they worked together they'd do it in half the time
i.e 5 days
Answer:
Step-by-step explanation:
Given expression is,

To prove this identity we will take the right side of the identity,


![=\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5B%5Cfrac%7B2%281-%5Ctext%7Btan%7D%5E2%5Cfrac%7BA%7D%7B2%7D%29%7D%7B2tan%5Cfrac%7BA%7D%7B2%7D%7D%5D)
[Since
]
= cot A
Hence right side of the equation is equal to the left side of the equation.
Answer:
3/4
Step-by-step explanation:
tan A =opposite/adjacent = 6/8 =3/4
Hope this helps
Have a good day