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3 years ago

What is the factorization of 81a6 - 100?

Mathematics

2 answers:

kolezko [41]3 years ago

8 0

Answer:

<em>C</em> - (9a³ - 10) x (9a³ + 10)

Mariana [72]3 years ago

7 0

The answer is (9a3-10) (9a3+10)

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Is 5x=y-4 a linear equation

julsineya [31]

Get y by it self and then graph it. Should be y=5x+4

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3 years ago

What is 47,300 in scientific notation?

agasfer [191]

There's always a decimal at the end of a whole number. here it's behind the last zero. move that decimal so that the non-zero digit is less than 10 but more than 1.
4.73, the decimal was moved 4 places to the left. so the scientific notation is
4.72X10^4

3 0

3 years ago

WILL GIVE 100 POINTS AND BRAINLIEST FOR BEST ANSWER

coldgirl [10]

Answer:

Step-by-step explanation:-16x^2 + 24x + 16 = 0.

A. Divide by 8:

-2x^2 + 3x + 2 = 0, A*C = -2*2 = -4 = -1 * 4. Sum = -1 + 4 = 3 = B, -2x^2 + (-x+4x) + 2 = 0,

(-2x^2-x) + (4x+2) = 0,

-x(2x+1) + 2(2x+1) = 0,

(2x+1)(-x+2) = 0, 2x+1 = 0, X = -1/2. -x+2 = 0, X = 2.

X-intercepts: (-1/2,0), (2,0).

B. Since the coefficient of x^2 is negative, the parabola opens downward. Therefore, the vertex is a maximum.

Locate the vertex: h = Xv = -B/2A = -24/-32 = 3/4, Plug 3/4 into the given Eq to find k(Yv). K = -16(3/4)^2 + 16(3/4) + 16 = 19. V(h,k) = V(3/4,19).

C. Choose 3 points above and below the vertex for graphing. Include the points calculated in part A which shows where the graph crosses the x-axis.

4 0

3 years ago

a small bridge sit atop for cube shaped powers that all have the same volume. The combined volume of the four pillars is 503 how

Natasha_Volkova [10]

Answer:

60 inches long are the sides of the pillars.

Step-by-step explanation:

Given : A small bridge sits atop four cube shaped pillars that all have the same volume. the combined volume of the four pillars is 500 ft cubed.

To find : How many inches long are the sides of the pillars?

Solution :

Refer the attached picture below for Clarence of question.

The volume of the cube is $V=a^3$

Where, a is the side.

The combined volume of the four pillars is 500 ft cubed.

The volume of each cube is given by,

$V=\frac{500}{4}=125\ ft^3$

Substitute in the formula to get the side,

$125=a^3$

$a=\sqrt[3]{125}$

$a=5\ ft$

We know, 1 feet = 12 inches

So, 5 feet = $5\times 12=60$ inches

Therefore, 60 inches long are the sides of the pillars.

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D-5x%2B6%7D%7B2x%5E%7B2%7D-7x%2B6%20%7D" id="TexFormula1" title="\frac{x^{

il63 [147K]

Answer:

$\frac{x-3}{2x-3}$ . hole or removable discontinuity at x=2

Step-by-step explanation:

Well generally if you want the simplest form, you factor each the denominator and numerator and then see if you can cancel any of the factors out (because they're in the denominator and numerator)

So let's start by factoring the first equation:

$x^2-5x+6$

Now let's find what ac is (it's just c since a=1...)

$AC= 6$

List factors of -6

$\pm1, \pm2, \pm3, \pm6$ .

Now we have to look for two numbers that add up to -5. It's a bit obvious here since there isn't many factors, but it's -2 and -3, and they're both negative since 6 is positive, and -5 is negative...

So using these two factors we get

$(x-2)(x-3)$

Ok now let's factor the second equation:

$2x^2-7x+6$

Multiply a and c

$AC = 12$

List factors of 12:

$\pm1, \pm2, \pm3, \pm4, \pm6, \pm12$ .

Factors that add up to -7 and multiply to 12:

$-3\ and\ -4$

Rewrite equation:

$2x^2-4x-3x+6$

Group terms:

$(2x^2-4x)+(-3x+6)$

Factor out GCF:

$2x(x-2)-3(x-2)$

Rewrite:

$(2x-3)(x-2)$

Now let's write out the equation using these factors:

$\frac{(x-2)(x-3)}{(2x-3)(x-2)}$ .

Here we can factor out the x-2 and the simplified form is:

$\frac{x-3}{2x-3}$

So we can "technically" define f(2) using the most simplified form, but it's removable discontinuity, so it has a hole as x=2. since it makes (x-2) equal to 0 (2-2) = 0.

8 0

2 years ago