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Ber [7]
3 years ago
14

A probability distribution showing the probability of success does not change from trial to trial, is termed a:

Mathematics
1 answer:
Mumz [18]3 years ago
3 0

Answer:

-uniform probability distribution

Step-by-step explanation:

In uniform probability distributions, the likelihood of each possible outcome happening or not is the same. This property means that, for any given trial, the probability that an event will be successful does not change. Take the probability of rolling a 5 on a die for instance, no matter how many trials are performed, there is always a 1 in 6 probability for each trial.

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4 0
2 years ago
49v2 + 42v<br> 56v3<br> Simplify rational expression
Alchen [17]

Answer:

Simplify each term.

49 v ^2  +  2352 v ^4

Step-by-step explanation:

5 0
3 years ago
7th grade math help me please :)
natka813 [3]

Answer:

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5 0
2 years ago
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No idea how to do this need help.
Arlecino [84]

Answer:

Hope that helps

Step-by-step explanation:

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3 0
2 years ago
Can someone answer these questions please, i'm having trouble with them
fiasKO [112]

Answer:

1. $686.94

2. $735.03

3. $10707.55

4. $17631.94

5. $19635.72

Step-by-step explanation:

1st Question:

The interest rate is 7% for each year. This means that each year the person has to pay 7% more than the previous amount. So we need to multiply the initial amount by (0.07+1=1.07) in order to get the interest for the first year. if we want to find the second year's interests then we will have to multiply 2 (1.07)'s and so on.

in this case our function is: 600*(1.07)^t=P(t)

when t=2 P(2)=600*(1.07)^2=$686.94

2nd Question:

Function: 600*(1.07)^t=P(t)

when t=3 P(3)=600*(1.07)^3=$735.03

3rd Question:

initial value=$8500

1+0.08=1.08

Function: 8500*(1.08)^t=P(t)

t=3

P(3)=8500*(1.08)^3=$10707.55

4th Question:

initial value=$12000

1+1.08=1.08

t=5

Function: P(t)=12000*(1.08)^t

P(5)=12000*(1.08)^5=$17631.94

5th Question:

Function: 14000*(1.07)^t=P(t)

P(5)=14000*(1.07)^5

P(5)=$19635.72

4 0
2 years ago
Read 2 more answers
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