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jolli1 [7]
3 years ago
11

Find the volume. Round your answer to the nearest tenth.

Mathematics
1 answer:
Simora [160]3 years ago
4 0

Answer:

94.6m³

Step-by-step explanation:

The diagram shown in this question is a trapezoidal prism.

The volume of a trapezoidal prism is calculated as:

L × H × (P + Q/2)

Where L = Length = 4m

H = Height = 4.3m

P = Base width = 8m

Q = Top width = 3m

The volume of the trapezoidal prism =

4 × 4.3 ×(8+3/2)

=4 × 4.3 ×(11/2)

= 94.6m³

Therefore, the volume of the trapezoidal prism to the nearest tenth = 94.6m³

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A card is drawn from a standard deck of 52 cards. What is the theoretical probability as a decimal of drawing the number 8? Roun
Alborosie

The answer would be 0.15 because in a deck there are only 4 cards of 8 (diamonds, hearts, clovers, and spades). Since there are 52 cards, you would divide 8 by 52 to get 0.153846, but since it says to round to the nearest hundredths, the answer would be 0.15.

8 0
3 years ago
What is the equation of the line that passes through (-2,2) and (1,-4)?
adelina 88 [10]

Answer:

y=-2x-2

Step-by-step explanation:

Slope: -4-2/1-(-2)=-6/3=-2

Equation: y=-2x+b

Substitute: 2=-2(-2)+b

2=4+b

b=-2

Therefore, y=-2x-2

I hope this helped and have a good rest of your day!

6 0
3 years ago
How do you solve the equation m^2=11m by factoring?
Natasha2012 [34]
m^2=11m
m^2-11m=0
m(m-11)=0
thus
\boxed{m=0\lor m=11}
3 0
3 years ago
. XYZ has vertices X (–5, 2), Y (0, –4), and Z (3, 3). What are the vertices of the image of X’Y’Z’ under the translation (x, y)
Katen [24]

Answer:

X' = (2, -3)

Y' = (7, -9)

Z' = (10, -2)

Step-by-step explanation:

to find the translation of each point substitute the x and y with the the numbers

eg; X ( -5,2) the x is 5 and the y is 2

so -5 + 7 = 2 (the x value)

2 - 5 = -3 ( the y value)

6 0
3 years ago
Which answer best describes the complex zeros of the polynomial function?
marysya [2.9K]

<u>Answer-</u>

<em>D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.</em>

<u>Solution-</u>

The given polynomial is,

f(x)=x^3-x^2+6x-6

The zeros of the polynomials are,

\Rightarrow f(x)=0

\Rightarrow x^3-x^2+6x-6=0

\Rightarrow x^2(x-1)+6(x-1)=0

\Rightarrow (x^2+6)(x-1)=0

\Rightarrow (x^2+6)=0,(x-1)=0

\Rightarrow x=\sqrt{-6},\ x=1

\Rightarrow x=1,\ \pm \sqrt6i

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

3 0
3 years ago
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