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loris [4]
4 years ago
15

Meena sells apple pies at the farmers market. She charges $12 for each pie. It costs her $5 to make each pie and there is a $35

fee she must pay each week to have a booth at the market.
Write and solve an inequality to find the numbet of pies meena must sell each week in order to make a profit?
Mathematics
1 answer:
Lina20 [59]4 years ago
3 0
12-5=7, and 7times 5 is 35 so Meena needs to make at least 8 pies to make a profit which would be $5

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1. Find the perimeter of the figure. Each unit is 1 centimeter​
Oxana [17]

Answer:

20

Step-by-step explanation:

count the sides of the boxes for each side of the shape

8 0
3 years ago
Use the information in the diagram to determine the height of the tree to the nearest foot.
Illusion [34]
The answer is 80 ft. 

Based on the diagram we know that the tree triangle and the building triangle are similar triangles where the lengths of each are proportional to the other. 

The lengths of the triangle the tree makes are half of the lengths of the building triangle. So this problem can be solved using ratio and proportion:

\frac{144}{160} =  \frac{72}{x}

to solve for x, all you need to do is cross multiply then divide. 

\frac{160*72}{144} =x

The answer is then 80ft.

Another way to solve this is just by using logic. If the lengths of the tree triangle is half of the building, simply divide the lengths of the building triangle by two. 

160ft/2 = 80ft. 

8 0
3 years ago
AYEEE CAN SOMEONE PLEASE HELP ME WITH THESE QUESTIONS????
Anettt [7]
Is it y=mx+b because if it is then plug the numbers in
7 0
3 years ago
Ok so i need help,what is 5% of 225
aivan3 [116]
If you would like to know what is 5% of 225, you can calculate this using the following steps:

x = 5% of 225
x = 5/100 * 225
x = 11.25

Result: 5% of 225 is 11.25.
3 0
4 years ago
Read 2 more answers
Use lagrange multipliers to find the point on the plane x − 2y + 3z = 6 that is closest to the point (0, 2, 5).
horsena [70]
Lagrangian:

L(x,y,z,\lambda)=x^2+(y-2)^2+(z-5)^2+\lambda(x-2y+3z-6)

where the function we want to minimize is actually \sqrt{x^2+(y-2)^2+(z-5)^2}, but it's easy to see that \sqrt{f(\mathbf x)} and f(\mathbf x) have critical points at the same vector \mathbf x.

Derivatives of the Lagrangian set equal to zero:

L_x=2x+\lambda=0\implies x=-\dfrac\lambda2
L_y=2(y-2)-2\lambda=0\implies y=2+\lambda
L_z=2(z-5)+3\lambda=0\implies z=5-\dfrac{3\lambda}2
L_\lambda=x-2y+3z-6=0

Substituting the first three equations into the fourth gives

-\dfrac\lambda2-2(2+\lambda)+3\left(5-\dfrac{3\lambda}2\right)=6
11-7\lambda=6\implies \lambda=\dfrac57

Solving for x,y,z, we get a single critical point at \left(-\dfrac5{14},\dfrac{19}7,\dfrac{55}{14}\right), which in turn gives the least distance between the plane and (0, 2, 5) of \dfrac5{\sqrt{14}}.
7 0
3 years ago
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