What is the area of the parallelogram. A. 131.1 m² B. 197.34 m² C. 262.2 m² D. 394.68 m²
2 answers:
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The correct question is
<span>Teresa graphs the following 3 equations: y=2x, y=x2+2, and y=2x2. She says that the graph of y=2x will eventually surpass both of the other graphs. Is Teresa correct? Why or why not?
we have that
y=2x
y=x</span>²+2
y=2x²
using a graph tool
see the attached figure
<span>We can affirm the following
</span>the three graphs present the same domain-----> the interval (-∞,∞)
The range of the graph y=2x is the interval (-∞,∞)
The range of the graphs y=x²+2 and y=2x² is the interval [0,∞)
therefore
<span>Teresa is not correct because the graph of y = 2x will not surpass the other two graphs since in the interval of [0, infinite) the three graphs present the same range</span>
<span>Teresa graphs the following 3 equations: y=2x, y=x2+2, and y=2x2. She says that the graph of y=2x will eventually surpass both of the other graphs. Is Teresa correct? Why or why not?
we have that
y=2x
y=x</span>²+2
y=2x²
using a graph tool
see the attached figure
<span>We can affirm the following
</span>the three graphs present the same domain-----> the interval (-∞,∞)
The range of the graph y=2x is the interval (-∞,∞)
The range of the graphs y=x²+2 and y=2x² is the interval [0,∞)
therefore
<span>Teresa is not correct because the graph of y = 2x will not surpass the other two graphs since in the interval of [0, infinite) the three graphs present the same range</span>
Answer:
Win=436584.2477 cm3/min
Step-by-step explanation:
Volume for a conical tank
V=π/3 r^2 h
We need a relation between r and h
r/h=252.5/1301.3=0.194 --> r=0.194h
sust. in Volume equation
V=π/3 (0.194r)^2 h=0.0394h^3
taking derivative with time respect in both sides
dV/dt=3(0.0394) h^2 dh/dt and we know when h=404cm, dh/dt=22.022 cm/min
dV/dt=3(0.0394)(404)^2 (22.022)=424984.2477 cm^3/min
Also, we know
dV/dt=Win-Wout and Wout=Win-11600.01160
Finally
Win=424984.2477+11600.0116
Answer
Win=436584.2477 cm3/min
