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3 years ago

HELP PLEASE !!!!!

Mathematics

1 answer:

Ivahew [28]3 years ago

3 0

$\sum_{k=4}^8(2k+2)=2\cdot4+2+2\cdot5+2+2\cdot6+2+2\cdot7+2+2\cdot8+2\\
\sum_{k=4}^8(2k+2)=10+12+14+16+18\\
\sum_{k=4}^8(2k+2)=70$

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Scott burned 20 calories per minute jogging for x minutes and 5 calories per minute for biking for y minutes. He spent a total o

stiv31 [10]

Answer:

x = 112

Step-by-step explanation:

We can create two equations 1. one that calculates calories burned and 2.another that calculates minutes:

20*x + 5*y = 1200

x + y = 120

Then we can solve for x

x = 120 - y

then we can plug that into the top equation:

20(120 - y) + 5y = 1200

divide by 5:

4(120 - y) + y = 240

distribute:

480 - 4y + y = 240

and then do all that combining like factors what not and simplify and solve:

480 - 3y = 240

-3y = -240

y = 8

NOW WE CAN JUST PLUG IN THE ANSWER FOR Y TO FIND X

8+x =120

x = 112

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3 years ago

Yosef purchased a new sweater. The total price of the sweater, including the 8% sales tax, was $16.74. What was the retail cost

Yanka [14]

Answer:

15.40, lol yeet, this one's EZ

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3 years ago

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777dan777 [17]

Real world example could be:
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3 years ago

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3 years ago

The first term of a geometric sequence is 32, and the 5th term of the sequence is 818 .

sammy [17]

Answer:

$32,24,18,\frac{27}{2} ,\frac{81}{8}$

Step-by-step explanation:

Let x, y , and z be the numbers.

Then the geometric sequence is $32,x,y,z,\frac{81}{8}$

Recall that term of a geometric sequence are generally in the form:

$a,ar,ar^2,ar^3,ar^4$

This implies that:

a=32 and $ar^4=\frac{81}{8}$

Substitute a=32 and solve for r.

$32r^3=\frac{81}{8}$

$r^4=\frac{81}{256}$

Take the fourth root to get:

$r=\sqrt[4]{\frac{81}{256} }$

$r=\frac{3}{4}$

Therefore $x=32*\frac{3}{4} =24$

$y=24*\frac{3}{4} =18$

$z=18*\frac{3}{4} =\frac{27}{2}$

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3 years ago