4 years ago

HELP PLEASE !!!!!

1 answer:

3 0

$\sum_{k=4}^8(2k+2)=2\cdot4+2+2\cdot5+2+2\cdot6+2+2\cdot7+2+2\cdot8+2\\
\sum_{k=4}^8(2k+2)=10+12+14+16+18\\
\sum_{k=4}^8(2k+2)=70$

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