Answer:
19375
Step-by-step explanation:
625*31=19375
Assuming ‘I’ is an imaginary unit . . .
Answer : -52 + 38i
<em>Note: Your expression sounds a little unclear, so I am assuming your expression is </em>

<em>But, the procedure to solve the expressions involving exponents remains the same, so whatever the expression is, you may be able to get your concept clear. </em>
<em>In the end, I will solve </em><em>both expressions</em><em>.</em>
Answer:
Please check the explanation
Step-by-step explanation:
Given the expression

solving the expression




Therefore, we conclude that:

IF YOUR EXPRESSION IS THIS
↓

solving the expression
as

so


Thus, the expression becomes

Answer:
irrational
Step-by-step explanation:
The x-value of A would be 5 because it is on (5,3)