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2 years ago

8. To calculate 159 - 73, a student writes the follow-

Mathematics

1 answer:

Evgen [1.6K]2 years ago

7 0

The question is an illustration of solving equations using estimates.

The student's strategy makes sense because he uses estimation to solve the given equation

The correct sequence of equation is as follows:

$\mathbf{159 - 73}$

$\mathbf{159 - 73 =160 - 70- 1 - 3}$

$\mathbf{159 - 73 =90- 4}$

$\mathbf{159 - 73 =86}$

We have:

$\mathbf{159 - 73}$

Add 0 to the equation

$\mathbf{159 - 73 =159 + 0- 73}$

Express 0 as 1 - 1

$\mathbf{159 - 73 =159 + 1 - 1- 73}$

$\mathbf{159 - 73 =160 - 1- 73}$

Add another 0

$\mathbf{159 - 73 =160 - 1- 73 + 0}$

Express 0 as 3 - 3

$\mathbf{159 - 73 =160 - 1- 73 + 3 - 3}$

$\mathbf{159 - 73 =160 - 1- 70 - 3}$

Rewrite as:

$\mathbf{159 - 73 =160 - 70- 1 - 3}$

Solve

$\mathbf{159 - 73 =90- 4}$

$\mathbf{159 - 73 =86}$

Read more about estimation and equations at:

brainly.com/question/18454732

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<h2>Answer:</h2>

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Pre-Algebra

Order of Operations: BPEMDAS

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Parenthesis
Exponents
Multiplication
Division
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Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
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Algebra I

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Calculus

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Basic Power Rule:

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Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

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Step 2: Differentiate

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Step 3: Solve

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x-coordinate

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