First note that f(x) means the same thing as y. To solve for f(x) or y you need to plug in -5 for x and solve using the rules of PEMDAS
5(-5) + 40
-25 + 40
15
When x is -5 then y is 15
Hope this helped!
~Just a girl in love with Shawn Mendes
There are infinite equivalent expressions. Here are some:
1/5(m-100)
20(1/100m-1)
1/5m-(4•5)
If you expand any of these or any of the terms, you will get an equivalent expression.
Answer:
Step-by-step explanation:
Part A
We will use the slope intercept form of the line and then convert later.
Equation
y = mx + b is the general form
Givens
Two data points
(4,180)
(9,325)
Solution
325 = 9x + b
<u>180 = 4x + b</u> Subtract
145 = 5x Divide by 5
145/5 = 5x/5 Do the division
29 = x This represents the cost / day
180 = 4x + b Substitute x = 29 to find b
180 = 4*29 + b Combine
180 = 116 + b Subtract 116 from both sides.
180 - 116 = b
64 = b
Solution for y = mx + b
y = 29x + 64
In Standard form this is
- 29x + y = 64 But the first number must be plus
29x - y = - 64 <<<< Answer A
Part B
y = 29x + 64
f(x) = 29x + 64
Part C
The graph is shown below. Various points are filled in using y = 29x + 64. The y intercept is (0,64) which is labeled. Let x = 1 , 2, 3, 4, ... 10 (which is arbitrary). This may be more easily done on a spreadsheet if you know how to use one to make graphs.
Answer:
180 hamburgers
120 hotdogs
Step-by-step explanation:
In this question, we are asked to calculate the number of hamburgers and hotdogs sold by a company given the amount made by them and the total number of these snacks sold
We proceed as follows;
Let the amount of hotdogs sold be x and the amount of hamburgers sold be y.
We have a total of 300 snacks sold, mathematically;
x + y = 300 ..........(I)
Now let’s look at the prices.
x number of hotdogs sold at $2, this give a total of $2x hotdogs
y number of hamburgers sold at $3, this give a total of $3y.
Adding both to give total, we have ;
2x + 3y = 780.......(ii)
This means we have two equations to solve simultaneously. From equation 1, we can say x = 300 -y
Now let’s insert this in the second equation;
2(300-y) + 3y = 780
600-2y + 3y = 780
y = 780-600 = 180
Recall; x + y = 300
x = 300 -y
x = 300-180 = 120
