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2 years ago

12

kim needs to read 147-page book for class. she has one week to read it, and she plans to read an equal amount of pages each day.

how many pages she needs to read per day to be prepared for class?

1 answer:

kipiarov [429]2 years ago

7 0

21 pages. you divide 147 by 7 and get 21 pages

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1 year ago

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$\\$

Step-by-step explanation:

Given:

Radius of the cylinder = 7 cm
Height of the cylinder = 10 cm

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To Find:

Curved surface area
Volume

$\\$

Solution:

$\\$

Using formula:

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{CSA \: of \: cylinder = 2\pi rh}}}}}} \: \star \\ \\$

<em>Substituting the required values: </em>

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$\dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times \dfrac{22}{7} \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 2 \times 22 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 44 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf CSA {(cylinder)} = 440 \: {cm}^{2} \\ \\ \\$

Now,

$\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{ \purple{Volume {(cylinder)}= \pi {r}^{2} h}}}}}} \: \star \\ \\ \\$

<em>Substituting the required values, </em>

$\\$

$\dashrightarrow \: \: \sf Volume {(cylinder)}= \dfrac{22}{7} \times {(7)}^{2} \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= \frac{22}{7} \times 49 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 22 \times 7 \times 10 \\ \\ \\ \dashrightarrow \: \: \sf Volume {(cylinder)}= 1540 {cm}^{3} \\ \\ \\$

Hence,

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