Calculate P(A or B) where A and B are mutually exclusive events and P(A) = 1 and P(B) =

Mathematics

1 answer:

34kurt3 years ago

3 0

Answer:

Step-by-step explanation:

If A and B are mutually exclusive and A is certain to happen, then B is certain to never happen, so P(B) = 0. The probability of either of two mutually exclusive events is the sum of their individual probabilities:

P(A or B) = P(A) +P(B) = 1 + 0

P(A or B) = 1

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Y=1/2x+3 -x+27=-6 solve using substitution

Nat2105 [25]

Answer:

y= 19.5 x=33

Step-by-step explanation:

-x + 27= -6

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-x= -33

(divide by negative 1 on both sides)

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(substitute x into the first equation)

y= 1/2x + 3

y= 1/2(33) +3

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3 years ago

What is the Quotient of 1 and 2/3 divided by 2 and 3/5

Nostrana [21]

Answer:

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Step-by-step explanation:

For division of mixed numbers, it often works well to first convert them to improper fractions. Then the division proceeds in the usual way: "invert and multiply", or "dot, swap."

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