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Dafna11 [192]
1 year ago
10

Slove equations with variables on both sides9 + 3f = 2f

Mathematics
1 answer:
Vera_Pavlovna [14]1 year ago
4 0

Given 9 + 3f = 2f

9 = 2f - 3f

9 = -f

f = -9

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An equiangular triangle has one side of length six inches. What is the height of the triangle, drawn from that side, to the near
Mandarinka [93]

9514 1404 393

Answer:

  5.2 in

Step-by-step explanation:

An equiangular triangle is also equilateral. All sides will be 6 inches, and the height line will be a perpendicular bisector of the side.

Using trig, the height is ...

  (3 in)tan(60°) = 3√3 in ≈ 5.2 in

Using the Pythagorean theorem, ...

  h² = 6² -3² = 27

  h = √27 ≈ 5.2 . . . inches

6 0
2 years ago
find the centre and radius of the following Cycles 9 x square + 9 y square +27 x + 12 y + 19 equals 0​
Citrus2011 [14]

Answer:

Radius: r =\frac{\sqrt {21}}{6}

Center = (-\frac{3}{2}, -\frac{2}{3})

Step-by-step explanation:

Given

9x^2 + 9y^2 + 27x + 12y + 19 = 0

Solving (a): The radius of the circle

First, we express the equation as:

(x - h)^2 + (y - k)^2 = r^2

Where

r = radius

(h,k) =center

So, we have:

9x^2 + 9y^2 + 27x + 12y + 19 = 0

Divide through by 9

x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0

Rewrite as:

x^2  + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}

Group the expression into 2

[x^2  + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}

[x^2  + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}

Next, we complete the square on each group.

For [x^2  + 3x]

1: Divide the coefficient\ of\ x\ by\ 2

2: Take the square\ of\ the\ division

3: Add this square\ to\ both\ sides\ of\ the\ equation.

So, we have:

[x^2  + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}

[x^2  + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2

Factorize

[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2

Apply the same to y

[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}

Add the fractions

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}

[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}

Recall that:

(x - h)^2 + (y - k)^2 = r^2

By comparison:

r^2 =\frac{7}{12}

Take square roots of both sides

r =\sqrt{\frac{7}{12}}

Split

r =\frac{\sqrt 7}{\sqrt 12}

Rationalize

r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}

r =\frac{\sqrt {84}}{12}

r =\frac{\sqrt {4*21}}{12}

r =\frac{2\sqrt {21}}{12}

r =\frac{\sqrt {21}}{6}

Solving (b): The center

Recall that:

(x - h)^2 + (y - k)^2 = r^2

Where

r = radius

(h,k) =center

From:

[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}

-h = \frac{3}{2} and -k = \frac{2}{3}

Solve for h and k

h = -\frac{3}{2} and k = -\frac{2}{3}

Hence, the center is:

Center = (-\frac{3}{2}, -\frac{2}{3})

6 0
2 years ago
Lucy was running a 10 mile race and the graph represents her running pace for the race. If the x-axis represents miles ran and t
Ostrovityanka [42]

Answer:

C

Step-by-step explanation:

The function multiplies by 8 so 6 would be 48 and 10 would be 80.

Have a great day!

4 0
3 years ago
Drawing it out would be best can you help me please
leva [86]

Answer:

z_1+z_2 = (-2,5)

Step-by-step explanation:

To Find: z_1+z_2

Solution :

Referring the given graph

We can find the coordinates of   z_1 and  z_2

Coordinates of   z_1= (-7,1)

Coordinates of  z_2= (5,4)

Thus Coordinates of  z_1+z_2 = (-7+5,1+4) = (-2,5)

Thus z_1+z_2 = (-2,5)

So, the point z_1+z_2 = (-2,5) is shown on the attached graph file

6 0
2 years ago
How do I write this expression:The quantity seven plus Z, squared
Dmitry_Shevchenko [17]

Answer:

  (7+Z)²

Step-by-step explanation:

A less ambiguous way to describe the quantity might be "the square of the quantity seven plus Z".

As it is, we rely on the presence of the comma to tell us that the quantity to be squared is (7+Z). If the comma were not present, we would assume you want to add 7 to the square of Z: 7+Z².

  the quantity 7 plus Z: (7+Z)

  that quantity squared: (7+Z)²

6 0
3 years ago
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