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Tanya [424]
3 years ago
13

A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is

55% salt and Solution B is 80% salt. She wants to obtain 130 ounces of a mixture that is 75% salt. How many ounces of each solution should she use?
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
5 0

Answer:

  • 26 ounces of 55% solution
  • 104 ounces of 80% solution

Step-by-step explanation:

Let x represent the quantity of 80% solution. Then 130-x is the amount of 55% solution. The total amount of salt in the mix is ...

  0.80x +0.55(130 -x) = 0.75·130

  0.25x = 0.20·130 . . . . . . . subtract 0.55(130)

  x = 0.20/0.25(130) = 104

  130-x = 26

She should use 26 ounces of 55% solution and 104 ounces of 80% solution.

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Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

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5 = -36 + b
b = 41

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jenyasd209 [6]
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Which of the following Statements are true?
choli [55]

Answer: Only Statement 1 is True.

Step-by-step explanation:

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Given the graph of a function f. Identify the function by name. Then Graph, state domain & range in set notation:A) f(x) +2B
WARRIOR [948]

The function in the graph has the name of square function.

The domain of a function is all values of x the function can have. The domain of this function is all real numbers:

\mleft\lbrace x\in\R\mright\rbrace

The range of a function is all values of y the function can have. The range of this function is all positive numbers, including zero:

\mleft\lbrace y\in\R\mright|y\ge0\}

In order to graph f(x) + 2, we just need to translate the graph 2 units up. To find the new points, we need to increase all y-coordinates by 2:

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Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ 2}

Then, in order to graph f(x) - 2, we just need to translate the graph 2 units down. To find the new points, we need to decrease all y-coordinates by 2:

(-2, 2), (-1, -1), (0, -2), (1, -1), (2, 2)

Domain: {x ∈ ℝ}

Range: {y ∈ ℝ | y ≥ -2}

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11 months ago
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