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Tanya [424]
3 years ago
13

A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is

55% salt and Solution B is 80% salt. She wants to obtain 130 ounces of a mixture that is 75% salt. How many ounces of each solution should she use?
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
5 0

Answer:

  • 26 ounces of 55% solution
  • 104 ounces of 80% solution

Step-by-step explanation:

Let x represent the quantity of 80% solution. Then 130-x is the amount of 55% solution. The total amount of salt in the mix is ...

  0.80x +0.55(130 -x) = 0.75·130

  0.25x = 0.20·130 . . . . . . . subtract 0.55(130)

  x = 0.20/0.25(130) = 104

  130-x = 26

She should use 26 ounces of 55% solution and 104 ounces of 80% solution.

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Answer:

a) 20<h≤30.

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Step-by-step explanation:

The missing table is shown in attachment.

Part a)

We need to find the class interval that contains the median.

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We start adding the frequency from the top obtain the least cumulative frequency greater or equal to 15.

2+8+9=19

This corresponds to the class interval 20<h≤30.

Adding from the bottom also gives the same result.

Therefore the median class is 20<h≤30.

b) Since this is a grouped data we use the midpoint to represent the class.

The median is given by :

\frac{\sum \: fx}{ \sum\: f}

=  \frac{5 \times 3 + 15\times 8 + 25 \times 9 + 35 \times 7 + 45 \times 4}{30}

=  \frac{785}{30}

= 26.17

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