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katen-ka-za [31]
3 years ago
7

The table shows information about the numbers of hours 30 children spent on their tablets one evening. a) find the class interva

l that contains the median. B)work out an estimate for the mean number of hours

Mathematics
2 answers:
Bogdan [553]3 years ago
8 0

Answer:

a) 20<h≤30.

b) 26.17 hrs

Step-by-step explanation:

The missing table is shown in attachment.

Part a)

We need to find the class interval that contains the median.

The total frequency is

\sum \: f = 30

The median class corresponds to half

\frac{1}{2}  \sum \: f ^{th}  -  -  - value

That is the 15th value.

We start adding the frequency from the top obtain the least cumulative frequency greater or equal to 15.

2+8+9=19

This corresponds to the class interval 20<h≤30.

Adding from the bottom also gives the same result.

Therefore the median class is 20<h≤30.

b) Since this is a grouped data we use the midpoint to represent the class.

The median is given by :

\frac{\sum \: fx}{ \sum\: f}

=  \frac{5 \times 3 + 15\times 8 + 25 \times 9 + 35 \times 7 + 45 \times 4}{30}

=  \frac{785}{30}

= 26.17

sattari [20]3 years ago
6 0

Answer:

b) is 2.2

Step-by-step explanation:

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eimsori [14]

Answer:

8,920 ÷ 80=111.5

892 ÷ 8=111.5

89.2 ÷ 0.08=111.5

.892 ÷ 0.008=111.5

Step-by-step explanation:

6 0
2 years ago
The Kitchen committee purchased 76 boxes of cookies for Vacation Bible School,
iren2701 [21]
269 I think :) not sure
5 0
2 years ago
What’s 34x568 can’t find my Calculator
Brut [27]

Hi MayceeRhea15,

34x568 is 19,312 and don't worry about not being able to find your calculator, we have all been there before :)

Hope this helps

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4 0
3 years ago
Read 2 more answers
BD is the angle bisector of
AlexFokin [52]

Note: Let us consider, we need to find the m\angle ABC and m\angle DBC.

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The m\angle ABC and m\angle DBC.

Solution:

BD is the angle bisector of ABC. So,

m\angle ABD=m\angle DBC

3x=x+20

3x-x=20

2x=20

Divide both sides by 2.

x=\dfrac{20}{2}

x=10

Now,

m\angle DBC=(x+20)^\circ

m\angle DBC=(10+20)^\circ

m\angle DBC=30^\circ

And,

m\angle ABC=(3x)^\circ+(x+20)^\circ

m\angle ABC=(4x+20)^\circ

m\angle ABC=(4(10)+20)^\circ

m\angle ABC=(40+20)^\circ

m\angle ABC=60^\circ

Therefore, m\angle DBC=30^\circ,m\angle ABD=30^\circ and m\angle ABC=60^\circ.

8 0
2 years ago
Question:
Setler79 [48]
To find equivalent equations, you simply have to simplify both of these :)

a)  5/6(x - 6) + 1/6(3 - x)

Simplify.

5/6x - 5 + 1/2 - 1/6x

Add like terms.

(5/6x - 1/6x) + (-5 + 1/2)

Simplify.

4/6x +(-4.5)

Simplify.

2/3x - 4.5

b) (y + 7)4 + 8 - 5y

Simplify.

4y + 28 + 8 - 5y

Add like terms.

(4y - 5y) + (28 + 8)

Simplify.

-y + 36

~Hope I helped!~
4 0
3 years ago
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