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2 years ago

Match the equation with the graph -0.4x-0.8y=0.10

Mathematics

1 answer:

laiz [17]2 years ago

7 0

Can't see the graph, but it should look something like this:

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Expand and simplify (x + 5)(x + 4)<br>

Nina [5.8K]

Answer:

(x+5)⋅(x+4)= x2+9x+20

Step-by-step explanation:

(x+5)(x+4)

+4x+5x+20=

+9x+20

7 0

3 years ago

Read 2 more answers

Can you help me please with this

miskamm [114]

-39/100 is the answer according to me ..

Plz mark me as brainliest if u found it helpful

6 0

2 years ago

Please help, this is due soon!

Oliga [24]

Before outlier : 7.25
After outlier : 4

7.25 - 4 = 3.25

So the mean decreases by 3.25 when the outlier is removed.

6 0

3 years ago

Sami’s mom went to the mall last Monday and decided that she wants to purchase a new computer soon. She read online that the pri

frozen [14]

Answer:

The y-intercept represents the price of the computer last Monday.

Step-by-step explanation:

The y-intercept is the point on a graph where x equals zero. Also, the y-intercept is the output value in an equation when x equals zero.

In this situation, x represents the number of days since last Monday. So, when x equals zero, no time has passed.

Therefore, the y-intercept represents the price of the computer last Monday.

7 0

2 years ago

Prove or disprove that the point (√5, 12) is on the circle centered at the origin and containing the point (-13, 0). Show your w

pav-90 [236]

Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.

<h3>What is the equation of a circle?</h3>

The equation of a circle of center $(x_0, y_0)$ and radius r is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

In this problem, the circle is centered at the origin, hence $(x_0, y_0) = (0,0)$ .

The circle contains the point (-13,0), hence the radius is found as follows:

$x^2 + y^2 = r^2$

$(-13)^2 + 0^2 = t^2$

$r^2 = 169$

Hence the equation is:

$x^2 + y^2 = 169$

Then, we test if point (√5, 12) is on the circle:

$x^2 + y^2 = 169$

$(\sqrt{5})^2 + 12^2 = 169$

25 + 144 = 169

Which is an identity, hence point (√5, 12) is on the circle.

More can be learned about the equation of a circle at brainly.com/question/24307696

#SPJ1

6 0

2 years ago