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3 years ago

5

The perimeter of a triangle is 33 centimeters. The first side is 5 centimeters shorter than the second, and the third is twice t

he first. Find the length of the sides.

1 answer:

Law Incorporation [45]3 years ago

3 0

first side is 7cm

second is 12cm

third is 14cm

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In an article about the cost of health care, Money magazine reported that a visit to a hospital emergency room for something as

baherus [9]

Answer:

Probability that the cost will be less than $500 is 0.95994 .

Step-by-step explanation:

We are given that Money magazine reported that a visit to a hospital emergency room for something as simple as a sore throat has a mean cost of $348 with a standard deviation of $87.

Let X = cost of a hospital emergency room visit for this medical service

So, X ~ N( $\mu=348, \sigma^{2} =87^{2}$ )

The standard normal z score distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

(a) Probability that the cost will be less than $500 = P(X < $500)

P(X < 500) = P( $\frac{X-\mu}{\sigma}$ < $\frac{500-348}{87}$ ) = P(Z < 1.75) = 0.95994 {from z table}

Therefore, the probability that the cost will be less than $500 is 0.95994 .

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3 years ago

Can someone help me please

ehidna [41]

Answer:

answer A

Step-by-step explanation:

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3 years ago

In the formula C = 2r, C stands for _____________a0

dexar [7]

C is twice the value of r.

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3 years ago

Use mathematical induction to prove

Alex17521 [72]

$Prove\ that\ the\ assumption \is \true for\ n=1\\1^3=\frac{1^2(1+1)^2}{4}\\ 1=\frac{4}{4}=1\\$

Formula works when n=1

Assume the formula also works, when n=k.

Prove that the formula works, when n=k+1

$1^3+2^3+3^3...+k^3+(k+1)^3=\frac{(k+1)^2(k+2)^2}{4} \\\frac{k^2(k+1)^2}{4}+(k+1)^3=\frac{(k+1)^2(k+2)^2}{4} \\\frac{k^2(k^2+2k+1)}{4}+(k+1)^3=\frac{(k^2+2k+1)(k^2+4k+4)}{4} \\\frac{k^4+2k^3+k^2}{4}+k^3+3k^2+3k+1=\frac{k^4+4k^3+4k^2+2k^3+8k^2+8k+k^2+4k+4}{4}\\\\\frac{k^4+2k^3+k^2}{4}+k^3+3k^2+3k+1=\frac{k^4+6k^3+13k^2+12k+4}{4}\\\frac{k^4+2k^3+k^2}{4}+\frac{4k^3+12k^2+12k+4}{4}=\frac{k^4+6k^3+13k^2+12k+4}{4}\\\frac{k^4+6k^3+13k^2+12k+4}{4}=\frac{k^4+6k^3+13k^2+12k+4}{4}\\$

Since the formula has been proven with n=1 and n=k+1, it is true. $\square$

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2 years ago

Calculate the radius of Circle M if the area is 28.26 square inches

damaskus [11]

The answe is 3in. Hope this helps!

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3 years ago