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sergiy2304 [10]
3 years ago
10

12(a−4) simplified I am confused with this question

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
8 0

Answer:

-48

Step-by-step explanation:

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Bolts are packed into bags at a factory. Each bag should have 25 bolts in it but a bad with 22 or 28 is acceptable. Formulate an
Viefleur [7K]

Answer:

Absolute value equation is; |x - 25| ≤ 3

Minimum number of bolts is 22 while Maximum number of bolts is 28

Step-by-step explanation:

We are told that;

Each bag should have 25 bolts in it but 22 or 28 is acceptable.

Since 22 or 28 is acceptable, it means the allowable error is ±3.

Thus, if x is the number of bolts in the bag, the absolute value equation would be;

|x - 25| ≤ 3

Minimum number of bolts is 22 while maximum is 28

6 0
3 years ago
I know the selected answer is correct but I'm not too sure how to get that answer.
Kryger [21]

\tt{ Hey \: there , \: Mr.Panda \: ! } ;)

♨\large{ \tt{ E \: X \: P \: L \: A \: N \: A \: T \: I\: O \: N}}:

⤻ Before solving the given question , you should know the answer of these questions :

✺How do you find the hypotenuse , perpendicular and base when the angle ( \theta \: , \alpha  \:  ,\beta ) is given ?

⇾ The longest side , which is the opposite side of right angle is the hypotenuse ( h ). There are two other sides , the opposite and the adjacent. The naming of these sides depends upon which angle is involved. The opposite is the side opposite the angle involved and it is called the perpendicular ( p ) . The adjacent us the side next to the angle involved ( buy not the hypotenuse ) and it is called the base ( b ).

☄ \large{ \tt{REMEMBER}} :

  • \bf{ \sin \theta =  \frac{opposite}{hypotenuse}  =  \frac{perpendicular}{hypotenuse}  }

  • \bf{ \cos\theta =  \frac{adjacent}{hypotenuse}  =  \frac{base}{hypotenuse}  }

  • \bf{ \tan \theta =  \frac{opposite}{adjacent}  =  \frac{perpendicular}{base}  }

In the above cases , \theta is taken as the angle of reference.

♪ Our Q/A part ends up here! Let's start solving the question :

❈ \large{ \tt{GIVEN}} :

  • Perpendicular ( p ) = ? , Hypotenuse ( h ) = 18 & base ( b ) = 16

✧ \large{ \tt{TO \: FIND} : }

  • Value of tan \theta

✎ \large{ \tt{SOLUTION}} :

Firstly , Finding the value of perpendicular ( p ) using Pythagoras theorem :

❃ \boxed{ \sf{ {h}^{2}  =  {p}^{2}  +  {b}^{2} }} [ Pythagoras theorem ]

\large{ ⇢ \sf{p}^{2}  +  {b}^{2}  =  {h}^{2} }

\large{⇢ \sf{ {p}^{2}  =  {h}^{2}  -  {b}^{2} }}

\large{ ⇢\sf{ {p}^{2}  =  {18}^{2}  -  {16}^{2} }}

\large{⇢ \sf{ {p}^{2}  = 324  - 256}}

\large{⇢ \sf{ {p}^{2}  = 68}}

\large{⇢ \sf{p =  \sqrt{68}}}

\large{ ⇢\sf{p =  \boxed{ \tt{2 \sqrt{17}}} }}

Okey, We found out the perpendicular i.e \tt{2 \sqrt{17}} . Now , We know :

❊ \large{ \sf{ \tan \theta} =  \frac{perpendicular}{base} }

\large {\tt{↬ \: tan \theta =  \frac{2 \sqrt{17} }{16}}}

\large{ \tt{ ↬ tan  \theta =  \frac{ \cancel{2} \:  \sqrt{17} }{ \cancel{16} \:  \: 8} }}

\large{ \tt{ ↬ \boxed{ \tt{tan \theta =  \frac{ \sqrt{17} }{8}}}}}

⟿ \boxed{ \boxed{ \tt{OUR\: FINAL \: ANSWER : \boxed{ \underline{ \bf{ \frac{ \sqrt{17} }{8}}}}}}}

۵ Yay! We're done!

♕ \large\tt{RULE \: OF \:SUCCESS }:

  • Never lose hope & keep on working ! ✔

ツ Hope I helped!

☃ Have a wonderful day / evening! ☼

# StayInAndExplore ☂

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3 0
3 years ago
Read 2 more answers
Compound interest compounded quarterly is given every ______ months. *<br> 1 point<br> 1<br> 3<br> 6
Ipatiy [6.2K]

Answer:

3 months

a quarter is a period of three months

Step-by-step explanation:

7 0
3 years ago
One angle of an octagon is 65º. The<br>others are equal to each other. Find them.​
r-ruslan [8.4K]

Answer:

42 1/7 degrees

Step-by-step explanation:

65+7x=360

7x=295

x=42 1/7

8 0
3 years ago
Read 2 more answers
6 children and 2 adults are going to the circus, children tickets are on sale, half the price of adult tickets totaling $54. How
inna [77]

Answer:

Price of 1 child ticket is $5.4

Price of 1 adult ticket is $10.8

Step-by-step explanation:

Given:-

6 children and 2 adults are going for circus.

Children ticket is half the price of adult ticket.

Total ticketing cost =$54

To find:-

Cost of 1 child ticket=?

Cost of 1 Adult ticket=?

Solution:-

Let price of 1 child ticket be x and price of 1 adult ticket be y,

therefore from the given data we get 2 equations,

6x+2y=54                          -----------------------------------(1)

x=\frac{1}{2} y                    --------------------------------(2)

Now, substituting the value of x from equation 2 in equation 1,

6x+2y=54

6(\frac{1}{2} y)+2y=54

\frac{6}{2}y+2y=54

3y+2y=54

5y=54

\therefore y=\frac{54}{5}

\therefore y =10.8          ------------------------(3)

Now, substituting the value of y from equation 3 in equation 2,

x=\frac{1}{2} y

\therefore x=\frac{1}{2} \times 10.8       ------------(from equation 3)

\therefore x=\frac{10.8}{2}

\therefore x=5.4              ----------------------(4)

As, x is price of 1 child ticket and y is price of 1 adult ticket,

Therefore price of 1 child ticket is $5.4 and price of 1 adult ticket is $10.8

7 0
3 years ago
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