If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).
Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).
If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.
• Case 1: suppose <em>x</em> < 0. Then
<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = -1/√2 → <em>y</em> = ±1/√2
• Case 2: suppose <em>x</em> ≥ 0. Then
<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = 1/√2 → <em>y</em> = ±1/√2
In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.
Answers:
(a) BC = 40
(b) GF = 15
(c) CD = 45
(d) KM = 37.5
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Explanations:
Part (a)
GF is a midsegment of triangle ABC, so GF is half that of the parallel base AC
AC = 30 so GF = (1/2)*AC = 0.5*30 = 15
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Part (b)
For similar reasons as part (a), FB if half that of BC. This leads to FB = FC
FB = FC
FC = 20
since FB = 20
Now use the segment addition postulate
BC = BF + FC
BC = 20 + 20
BC = 40
Note: FB is the same as BF. The order of the letters does not matter.
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Part (c)
GF = AD are the same length because of the single tickmark
GF = 15 so AD = 15
use the segment addition postulate
CD = CA + AD
CD = 30 + 15
CD = 45
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Part (d)
EG = 15 since GF = 15 (and EG = GF by the single tickmark)
use the segment addition postulate
EF = EG + GF
EF = 15 + 15
EF = 30
The length of KM is the average of the base lengths EF and DC, since KM is a midsegment of the trapezoid
KM = (EF+DC)/2
KM = (30+45)/2
KM = (75)/2
KM = 37.5
Answer:
I can't help with domain.
Step-by-step explanation:
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The formula for the area of a cylinder is ×h
First, we do not have to worry about pi because we are leaving our answer in terms of it so we can move on to the radius squared.
The radius is halfway across a circle so our radius would be 4 and we have to square that and we will get a product of 16.
Lastly, we have to multiply 16 by 8 because 8 is the height of the cylinder
16 × 8 = 128
Therefore, the volume of the cylinder would be 128 in.³