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lawyer [7]
2 years ago
13

Ava poured 3 gallons of paint equally into 5 cans. How many gallons of paint will there be in each can

Mathematics
2 answers:
FromTheMoon [43]2 years ago
5 0

Answer:

0.6 gallons/can

Step-by-step explanation:

Simply divide the gallons of paint by the number of cans:

\frac{3-gallons-of-paint}{5-cans} = 0.6 gallons/can

iogann1982 [59]2 years ago
4 0

Answer:

0.6 is the correct answer

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There are 4 red golf balls and 2 green golf balls in a bucket. You select a ball at random, keep it, and select again. Find the
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Answer:

C

Step-by-step explanation:

It should be 2/3 because there are 6 balls and two of them are green which gives the fraction 2/6 and can be reduced to 1/3

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3 years ago
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The coordinates of the midpoint of GH are M(-2, 0), and the coordinates of one endpoint are H(4,-4).
Svetlanka [38]

The coordinate of point S from the giving coordinate point is (-8,4)

<h3>Midpoint of coordinates</h3>

The formula for calculating the midpoint of coordinate point is expressed as:

M(x,y) = {(x₁+x₂)/2, (y₁+y₂)/2}

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x₂ = -4-4

x₂ = -8

Similarly

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0(2) = -4+y₂

y₂ = 4

Hence the coordinate of point S from the giving coordinate point is (-8,4)

Learn more on midpoint here: brainly.com/question/5566419

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4 0
1 year ago
What is the equation for a circle with a center at (-2,-4) that passes through the point (3,8)?
Margarita [4]
Check the picture below.

so, the center of the circle is the midpoint of that diametrical segment, and half that length is the radius.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -2 &,& -4~) &#10;%  (c,d)&#10;&&(~ 3 &,& 8~)&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{3-2}{2}~~,~~\cfrac{8-4}{2} \right)\implies \left( \frac{1}{2}~,~2 \right)\impliedby center

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ -2 &,& -4~) &#10;%  (c,d)&#10;&&(~ 3 &,& 8~)&#10;\end{array}~~~ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;d=\sqrt{[3-(-2)]^2+[8-(-4)]^2}\implies d=\sqrt{(3+2)^2+(8+4)^2}&#10;\\\\\\&#10;d=\sqrt{25+144}\implies d=\sqrt{169}\implies d=13\qquad\qquad \qquad  \stackrel{radius}{\frac{13}{2}}

\bf \textit{equation of a circle}\\\\ &#10;(x- h)^2+(y- k)^2= r^2&#10;\qquad &#10;center~~(\stackrel{\frac{1}{2}}{ h},\stackrel{2}{ k})\qquad \qquad &#10;radius=\stackrel{\frac{13}{2}}{ r}&#10;\\\\\\&#10;\left( x-\frac{1}{2} \right)^2+(y-2)^2=\left( \frac{13}{2} \right)^2\implies \left( x-\frac{1}{2} \right)^2+(y-2)^2=\frac{169}{4}

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3 years ago
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Answer: no.

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Answer:

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Step-by-step explanation:

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3 years ago
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