Answer:
The width is 50 yards and the length is 141 yards.
Step-by-step explanation:
Let's call: L the length of the field and W the width of the field.
From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:
2L + 2W = 382
Because the perimeter of a rectangle is the sum of two times the length with two times the width.
Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:
L = 3W - 9
So, replacing this last equation on the first one and solving for W, we get:
2L + 2W = 382
2(3W - 9) + 2W = 382
6W -18 +2W = 382
8W - 18 = 382
8W = 382 + 18
8W = 400
W = 400/8
W = 50
Replacing W by 50 on the following equation, we get:
L = 3W - 9
L = 3(50) - 9
L = 141
So, the width of the rectangular field is 50 yards and the length is 141 yards.
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CIRCUMFERENCE
- The distance all around the circle. Calculated:
.
PI
- An irrational number. Equals the ratio of a circle's circumference to its diameter. It's approximately 3.
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Answer:
8
Step-by-step explanation:
first you should convert anyone of them to the other
1 ft = 12 in
the ratio = 96/12 = 8
Answer:
4.5
Step-by-step explanation:
To solve for the mean (average), you need to add together all the numbers then divide by how many numbers there are. In this case, there are 10 numbers.
2+7+5+4+3+3+5+5+6+5 = 45
45/10 = 4.5
