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mestny [16]
3 years ago
13

How do I do this please help I'm in tears

Mathematics
2 answers:
irakobra [83]3 years ago
3 0
F(x) is vertically stretched by a factor of 5/4 matches w/ f(x)-5/4
f(x) reflects the x axis matches w/ -f(x)
f(x) is translated 5/4 units up matches with f(x)+5/4
f(x) translated 5/4 to the left matches w/ f(x)-5/4

I didn't really know about this one but it seemed kind of easy, what was your first guesses and did you forget to put one more or was the question like that.


Hope this is right :) or if someone else has a different answer but in the meantime, good luck :)
ddd [48]3 years ago
3 0

Step-by-step explanation:

We know that,

Translation shifts the figure in horizontal or vertical direction.

Reflection flips the figure around a line.

Dilation changes the size of the figure.

Now, using above information, we see that,

f(x+\frac{5}{4}) represents that the function is translated horizontally \frac{5}{4} units to the left.

f(x)+\frac{5}{4} represents that the function is translated vertically \frac{5}{4} units upwards.

f(x)-\frac{5}{4} represents that the function is translated vertically \frac{5}{4} units downwards.

-f(x) represents that the function is reflected across x-axis.

The transformations applieed can be viewed in the figure below.

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Alina has just received 333 video games for her birthday to add to her existing 121212 video games. A week later she went to the
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Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

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12 girls for every 5 boys
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girls/boys

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answer is B

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3 years ago
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Please help I’m timed
liubo4ka [24]
SAS is the correct answer
6 0
3 years ago
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