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4 years ago

At 20 meters from a flagpole, the angle of elevation is 48 degrees, how tall is the flagpole

Mathematics

1 answer:

Ira Lisetskai [31]4 years ago

3 0

ANSWER:

The height of flag pole is 24 meters.

SOLUTION:

Given, at 20 meters from a flagpole, the angle of elevation is 48 degrees, We need to find how tall is the flag pole.

Let the length of the flag pole be x.

In the given case, ground, flag pole and sight all together forms a right angle triangle.

In that triangle, sight acts as hypotenuse and remaining as sides.

Now, we know that, in any triangle.

$\tan \theta=\frac{\text {opposite side}}{\text {adjacent side}}$

Since, angle of elevation is 48 degrees and flag acts as opposite side, we get

$\tan (48)=\frac{x}{20}$

$1.200=\frac{x}{20}$

x = 1.200 x 20

x = 24.00

Hence, the height of flag pole is 24 meters.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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X and Y will be the same length and that will be hypotenuse * sqrt(2)/2. So
x = y = 8*sqrt(2) * sqrt(2)/2 = 8*2/2 = 8
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x = sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13
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y = sqrt(1000^2 - 600^2) = sqrt(1000000 - 360000) = sqrt(640000) = 800  5. A 45,45,90 right triangle. One leg known. The other leg will have the same length as the known leg and the hypotenuse can be discovered with the Pythagorean theorem.  x = 6. y = sqrt(6^2 + 6^2) = sqrt(36+36) = sqrt(72) = sqrt(2 * 36) = 6*sqrt(2), approximately 8.485281374
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x = y.
12^2 = x^2 + y^2
12^2 = x^2 + x^2
12^2 = 2x^2
144 = 2x^2
72 = x^2
sqrt(72) = x
6*sqrt(2) = x
x is approximately 8.485281374
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Answer:

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Step-by-step explanation:

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