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poizon [28]
3 years ago
10

At 20 meters from a flagpole, the angle of elevation is 48 degrees, how tall is the flagpole

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
3 0

<u>ANSWER: </u>

The height of flag pole is 24 meters.

<u>SOLUTION: </u>

Given, at 20 meters from a flagpole, the angle of elevation is 48 degrees,  We need to find how tall is the flag pole.

Let the length of the flag pole be x.

In the given case, ground, flag pole and sight all together forms a right angle triangle.

In that triangle, sight acts as hypotenuse and remaining as sides.

Now, we know that, in any triangle.

\tan \theta=\frac{\text {opposite side}}{\text {adjacent side}}

Since, angle of elevation is 48 degrees and flag acts as opposite side, we get

\tan (48)=\frac{x}{20}

1.200=\frac{x}{20}

x = 1.200 x 20

x = 24.00

Hence, the height of flag pole is 24 meters.

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Compute the directional derivative of the function g(x,y)= sin(π(x−5y)).
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Step-by-step explanation:

The directional derivative of a function in a particular direction u is given as the dot product of the unit vector in the direction of u and the gradient of the function

g(x,y) = sin(π(x−5y)

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In the circle below, DB = 22 cm, and m&lt;DBC = 60°. Find BC. Ignore my handwriting.​
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Answer:

BC=11\ cm

Step-by-step explanation:

step 1

Find the measure of the arc DC

we know that

The inscribed angle measures half of the arc comprising

m\angle DBC=\frac{1}{2}[arc\ DC]

substitute the values

60\°=\frac{1}{2}[arc\ DC]

120\°=arc\ DC

arc\ DC=120\°

step 2

Find the measure of arc BC

we know that

arc\ DC+arc\ BC=180\° ----> because the diameter BD divide the circle into two equal parts

120\°+arc\ BC=180\°

arc\ BC=180\°-120\°=60\°

step 3

Find the measure of angle BDC

we know that

The inscribed angle measures half of the arc comprising

m\angle BDC=\frac{1}{2}[arc\ BC]

substitute the values

m\angle BDC=\frac{1}{2}[60\°]

m\angle BDC=30\°

therefore

The triangle DBC is a right triangle ---> 60°-30°-90°

step 4

Find the measure of BC

we know that

In the right triangle DBC

sin(\angle BDC)=BC/BD

BC=(BD)sin(\angle BDC)

substitute the values

BC=(22)sin(30\°)=11\ cm

6 0
3 years ago
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