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vovikov84 [41]
3 years ago
14

Here is some record-keeping from a coffee shop about their paper cups. Cups are delivered 2,000 at a time. How many paper cups a

re left at the end of the day on Wednesday?

Mathematics
2 answers:
tatiyna3 years ago
8 0
1748 is the correct answer
Akimi4 [234]3 years ago
3 0

Answer:

1748

Step-by-step explanation:

Tuesday + Wednesday - Monday

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The population of a city is expected to increase by 7.5% next year. If p represents the current population, which expression rep
igor_vitrenko [27]

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1.75 p

Step-by-step explanation:

if you wouldn't mind giving me brainliest, i'm just trying to rank up.

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3 years ago
Solve the following quadratic function by utilizing the square root method. f(x) = 1 - x2 x = + [?]
faltersainse [42]

Answer:

Step 1) y=16-x2. Swap the sides so that all terms of the variables are on the left side. Step 2) 16-x_{2}=y. Subtract 16 from both sides. Step 3) -x_{2}=y-16 Divide the two sides by -1. Step 4). \frac{-x_{2}}{-1}=\frac{y-16}{-1} Dividing by -1 undoes the multiplication by -1. Step 5). x_{2}=\frac{y-16}{-1} Step 6) dived y-16 by -1 And the final answer = x_{2}=16-y

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
find the number of running and passing plays using substitution method 110 plays 3 yards per run 7 yards per pass total yards 37
Zinaida [17]

Let x be the number of running plays

Y  be the number of passing plays

Since the total plays is 110

 X + y = 110

And total yard is 378

3x + 7y = 378

Using the first equation

X = 110 – y and substitute to the 2nd equation

3(110 – y) + 7y = 378

And solve for y

Y = 12

Substitute to eqution 1

X = 110 – 12 = 98

7 0
3 years ago
Suppose that we are testing a coin to see if it is fair, so our hypotheses are: H0: p = 0.5 vs Ha: p ≠ 0.5. In each of (a) and (
aleksley [76]

Answer:

H_0: p = 0.5\\H_a: p \neq 0.5

a. We get 56 heads out of 100 tosses.

We will use one sample proportion test  

x = 56

n = 100

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{56}{100}

\widehat{p}=0.56

Formula of test statistic =\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

                                       =\frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}

                                       =1.2

refer the z table for p value

p value = 0.8849

a.  We get 560 heads out of 1000 tosses.

We will use one sample proportion test  

x = 560

n = 1000

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{560}{1000}

\widehat{p}=0.56

Formula of test statistic =\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

                                       =\frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}

                                       =3.794

refer the z table for p value

p value = .000148

p value of part B is less than Part A because part B have 10 times the number the tosses.

6 0
3 years ago
Convert the following to scientific notation: 0.009.
mote1985 [20]
The answer is:  [B]:  " 9 * 10⁻³ " .
____________________________________________________
5 0
3 years ago
Read 2 more answers
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