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3 years ago

What is the constant rate of change

Mathematics

2 answers:

Juli2301 [7.4K]3 years ago

3 0

X-3=y the constant rate of change is nine.

gtnhenbr [62]3 years ago

3 0

The answer is 1. 7/7 = 1

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Select the three images that represent a fraction that is equal to 6/8.

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Answer:

1 2 5

Step-by-step explanation:

right I got it right on the test

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3 years ago

Simplify this expression. 4(9n-9) a. -10n+20 b. -10n+19 c. 36n-36 d. -8n+56

lesya692 [45]

4(9n-9)
= 4*9n -4*9 (distributive property)
= 36n -36

The correct answer is c. 36n -36~

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4 years ago

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Mrs. Davis went to a produce market to buy bananas and strawberries. She spent $8.00. If the bananas were $0.50 per pound, and t

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Answer:

4 pounds

Step-by-step explanation:

Let b represent the pounds of bananas Mrs. Davis bought. The weight of strawberries would be (7-b) and their cost would be 4×0.50 = 2.00 per pound. Her total purchase was ...

0.50b + 2.00(7 -b) = 8.00

-1.50b +14 = 8 . . . . simplify

6 = 1.50b . . . . . . add 1.50b -8

4 = b . . . . . . . . divide by 1.50

Mrs. Davis bought 4 pounds of bananas.

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2 years ago

A triangle who has two sides to the links of 7 AM and 12 PM which of the following wants to represent the length of the third si

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Answer:

What do you mean by writing time?

Step-by-step explanation:

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3 years ago

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Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

4 years ago