It is given that in △ABC, AD ⊥ BC. Using the definition of sine with angle C in △ACD results in sin(C) = . Using the multiplicat
ion property of equality to isolate h, the equation becomes bsin(C) = h. Knowing that the formula for the area of a triangle is A = bh is and using the side lengths as shown in the diagram, which expression represents the area of △ABC? bsin(C) absin(C) cbsin(C) hbsin(C)
2 answers:
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Answer:
The distance between A and B is 8.5 after rounded to the nearest tenth
Step-by-step explanation:
The formula you always use for distance between points is as pictured.
Point A is (-6, 4), this is x1 and y1
Point B is (2, 1), this is x2 and y2
(2-[-6])^2 + (1-4)^2
since 2 negatives make a positive, 2 - -6 = 8
1 - 4 = -3
This makes 8 squared and -3 squared
8x8 = 64
-3x-3 = 9
64 + 9 = 73
the square root of 73 = 8.544003745
After rounding to the nearest tenth, it is 8.5
I hope this helps you! Good luck :)
