It is given that in △ABC, AD ⊥ BC. Using the definition of sine with angle C in △ACD results in sin(C) = . Using the multiplicat

Question

3 years ago

11

It is given that in △ABC, AD ⊥ BC. Using the definition of sine with angle C in △ACD results in sin(C) = . Using the multiplicat

ion property of equality to isolate h, the equation becomes bsin(C) = h. Knowing that the formula for the area of a triangle is A = bh is and using the side lengths as shown in the diagram, which expression represents the area of △ABC? bsin(C) absin(C) cbsin(C) hbsin(C)

Mathematics

2 answers:

amid [387] · Answer 1 · 2022-08-30T09:10:43+03:00

amid [387]3 years ago

7 0

We see here in the diagram that the base is a. We know this because the height is perpendicular to it. We also know the height is bsin(C) which, when replace h for bsin(C) and a for the base, we get A=absin(C), which is the second option.

shtirl [24] · Answer 2 · 2022-08-30T10:56:56+03:00

shtirl [24]3 years ago

6 0

Answer:

B

Step-by-step explanation: