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erastovalidia [21]
3 years ago
13

When can you use mathematics in real life situations

Mathematics
2 answers:
Ivahew [28]3 years ago
8 0
You need it in real life situation by having to keep track how much money you take in and out your bank account
Reptile [31]3 years ago
4 0

Answer:

Step-by-step explanation:

Equations are commonly used in scienctific discoveries to calculate power, work, distance, and time. It is also common to use the circumference and area equations to help with construction and design. Overall, math is a very important part of our lives, and it is also important to learn about it.

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Please answer correctly !!!!! Will mark Brianliest !!!!!!!!!!!!!!
Sedbober [7]

Answer:

24/25

Step-by-step explanation:

Please see the attached image.

The cosine of an angle is the adjacent side relative to that angle over the hypotenuse.

Answer: 24/25

8 0
2 years ago
The histogram below shows information about the number of hamburgers students ate in a month:
vovikov84 [41]
The answer is

D. The number of students who ate 10 hamburgers or more

100% Verified!

Hope This Helps!:)
6 0
4 years ago
¿Cual es el número cuya tercera parte más 12 da 26?<br>OK​
iren2701 [21]

Answer:

42

Step-by-step explanation:

x/3+12 = 26

Multiply everything by 3 to eliminate the fraction

x+36=78

subtract 36 on both sides

x=42

   

42/3=14

14+12=26

7 0
3 years ago
Find the area of the shaded region round to the nearest tenth
Alenkinab [10]

Answer: 818.4

Step-by-step explanation:

Using the area of a sector formula, we get the area of the entire sector is (\pi)(27.8^{2})\left(\frac{150}{360} \right).

Using the formula A=\frac{1}{2} ab \sin C, we get the area of the triangle is \frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}).

So, the area of the shaded sector is (\pi)(27.8^{2})\left(\frac{150}{360} \right)-\frac{1}{2}(27.8)(27.8)(\sin 150^{\circ}) \approx \boxed{818.4}

6 0
2 years ago
todd Has a collection of 8cds and sally has a collection of 18 cds Todd is adding 9cds a month to his collection while sally is
STatiana [176]

Answer:

Step-by-step explanation:

Let's create some equations first.

Say M = number of months, T = Todd and S = Sally.

We know that Todd starts with 8 cds and sally starts with 18 cds.

This means when M= 0,  T = 8 and S = 18

After one month (M = 1), Todd adds 9 cds.

This means can write the following equation:

T = 8 + 9M

So after the first month (where M = 1), we can find out that Todd has

T = 8 + 9 x 1 = 8 + 9 = 17 cds

For Sally, we know she adds 7 cds per month.

S = 18 + 7M

After one month (M = 1),

S = 18 + 7 x 1 = 25 cds.

Now we are trying to find when they will have the same number of cds and how many.

This means we are trying to figure out what M = ? when Todd and Sally are equal.

So we want to find when T = S

Remember, earlier we wrote :

T = 8 + 9M

S = 18 + 7M

If T = S, this means:

8 + 9M = 18 + 7M

Gather the like terms and solve for M.

Subtract 8 from both sides.

9M = 10 + 7M

Subtract 7M from both sides

2M = 10

Divide both sides by 2

M = 5.

So in 5 months, we are saying T = S (Todd and Sally will have the same number of cds).

Put M = 5 back into our earlier equations to find out how many cds they have after 5 months.

T = 8 + 9M

T = 8 + 9 x 5

T = 53

Therefore, after 5 months Todd and Sally will have 53 cds each :)

6 0
3 years ago
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