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3 years ago

When can you use mathematics in real life situations

Mathematics

2 answers:

Ivahew [28]3 years ago

8 0

You need it in real life situation by having to keep track how much money you take in and out your bank account

Reptile [31]3 years ago

4 0

Answer:

Step-by-step explanation:

Equations are commonly used in scienctific discoveries to calculate power, work, distance, and time. It is also common to use the circumference and area equations to help with construction and design. Overall, math is a very important part of our lives, and it is also important to learn about it.

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ALICE

Mice21 [21]

Answer:

Step-by-step explanation:

The 7 is in the hundredths place.

6 0

3 years ago

Y varies directly with x. When x is 4 y is 8. Find y when x = 10.

grandymaker [24]

Step-by-step explanation:

y = 4 when x = 8 So, 4 = 8k

k = 1/2

y = (1/2)x

Therefore, when x = 10, y = (1/2)(10) = 5

4 0

2 years ago

FIND THE AREA OF THE SHADED REGION. SHOW ALL YOUR WORK.

erik [133]

Answer:

he area that is un-shaded is (x-3)(x-6).

The entire area is (2x+2)(3x-4).

Area of the shaded region is:

(2x+2)(3x-4) - (x-3)(x-6) =

(6x2-2x-8) - (x2-9x+18) =

6x2-2x-8-x2+9x-18 =

5x2+7x-26 hopes this help btw (;

3 0

3 years ago

Read 2 more answers

There are 12 students running for three student coun-

anyanavicka [17]

Must be

(c) 12.11.10

Or

(d) 12

8 0

3 years ago

X²+Y²=250 and XY=117<br> What are the values of X and Y?

yan [13]

Answer:

Step-by-step explanation:

$x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}$

$y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9$

6 0

3 years ago