Let <em>f(x)</em> = (<em>x</em> ² - 1)³. Find the critical points of <em>f</em> in the interval [-1, 2]:
<em>f '(x)</em> = 3 (<em>x</em> ² - 1)² (2<em>x</em>) = 6<em>x</em> (<em>x </em>² - 1)² = 0
6<em>x</em> = 0 <u>or</u> (<em>x</em> ² - 1)² = 0
<em>x</em> = 0 <u>or</u> <em>x</em> ² = 1
<em>x</em> = 0 <u>or</u> <em>x</em> = 1 <u>or</u> <em>x</em> = -1
Check the value of <em>f</em> at each of these critical points, as well as the endpoints of the given domain:
<em>f</em> (-1) = 0
<em>f</em> (0) = -1
<em>f</em> (1) = 0
<em>f</em> (2) = 27
So max{<em>f(x)</em> | -1 ≤ <em>x </em>≤ 2} = 27.
The answer to the equation is 22
Hope this helps you
-AaronWiseIsBae
X = 15
Y= 1/2
2x = 30
2 = 4y
Hope this helps.
This is a common math problem. There are two ways to answer this question but both will give you the same answer. There is a misconception that this can also equal 40. If someone posts that the answer is 40, please let me know and I will explain why that is not actually the answer.
1+4=5 2+5=7
3+6=21
8+11=
These equations are actually:
1*(4+1)=52*(5+1)=7
3*(6+1)=21
8*(11+1)=96
Therefore:
8+11 = 96
Answer:
fifty five hundredths = 0.55
Step-by-step explanation:
Let's use 0.45 as an example. You read this decimal by using the place value of the last digit to the right of the decimal point.
This number is read as forty-five hundredths because the last digit is in the hundredths place.
