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Sonja [21]
3 years ago
11

Using algebra prove that the square of any odd number is always 1 more than a multiple of 8

Mathematics
1 answer:
Readme [11.4K]3 years ago
4 0
Start off with (x+1)(x-1). If x is 5 for example, use 4 and 6. For any odd number x, there are two even numbers next to it on the number line. One of these will be at least a multiple of 2 and one at least a multiple of 4. If you go to a number line, you see that in every group of 4 natural numbers has 2 odds and 2 evens. These evens include that multiple of 4 (or a greater power of 2) and that multiple of 2 (or greater power of 2).
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VikaD [51]
Just multiply the fractions by 32
3 0
4 years ago
Determine whether the given measures can be the lengths of the sides of a triangle write yes or no
ohaa [14]

NO.,the given measures can not be the lengths of the sides of a triangle

Step-by-step explanation

The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

so, Find the range for the measure of the third side of a triangle given the measures of two sides.

here given measures are 2,2,6

2+2 = 4 which is less than the third side 6

        = 4 < 6    

This not at all a triangle.

Hence, the given measures can not be the lengths of the sides of a triangle

3 0
4 years ago
Find the perimeter of a rectangle if one side is 3x and the other side is 6x.
dexar [7]

Answer:

18x

Step-by-step explanation:

2(3x+6x)

6 0
3 years ago
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Evgesh-ka [11]

Answer:

  • D-last pic

Step-by-step explanation:

Check the rate of change in the f(x) column.

The first 3 have linear change (arithmetic sequence) and the last one has different pattern.

Correct option is D

7 0
3 years ago
The numbers 1 through 15 are written on cards. One card is chosen at random. Event A is choosing a
lana [24]

Step-by-step explanation:

the probability is always the number of desired cases over the number of all possible cases.

in our situation we have 15 cards.

that is the total possible cases when a random card is chosen.

how many desired cases do we have ?

a number NOT a multiple of 5.

how many are there ?

it is easier to say how many numbers there are being a multiple of 5 : 5, 10, 15

so, 3 numbers out of the 15 are multiple of 5.

that means

15 - 3 = 12 numbers of the 15 are NOT multiples of 5.

so, the probability to draw a card that is not a multiple of 5 is

12/15 = 4/5 = 0.8

the information about event B and even numbers is irrelevant for the question.

6 0
2 years ago
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