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3241004551 [841]
3 years ago
11

The graph of f(x) = x3 + 6x2 + 12x + 8 is shown.

Mathematics
2 answers:
adelina 88 [10]3 years ago
5 0

Answer:

C) two real number solutions

Step-by-step explanation:

Norma-Jean [14]3 years ago
3 0
Two real number solutions
Hope this help
You might be interested in
Find the smallest solution to the equation 2/3 X² equals 24
iren [92.7K]

Answer:

The smallest solution is -6

Step-by-step explanation:

2/3 x^2 = 24

Multiply each side by 3/2

3/2 *2/3 x^2 = 24*3/2

x^2 = 36

Take the square root of each side

sqrt(x^2) = sqrt(36)

x = ±6

The smallest solution is -6

The largest solution is 6

4 0
4 years ago
What is the area of the two-dimensional cross section that is parallel to face ABC ?
Afina-wow [57]
The two triangle faces are congruent, so the missing side length on the top triangle is 24ft.
Area of a triangle = bh/2
7*24/2=84ft
Area = 84ft
8 0
3 years ago
Read 2 more answers
The sum of two numbers is 23. The difference of the numbers is 7.4. What are the two numbers?​
Brums [2.3K]
X+y=23
X-y=7.4

X+y=23
y=23-X

X-y=7.4
(23-y)-y=7.4
23-2y=7.4
-2y=-15.6
Y=7.8

X+y=23
X+7.8=23
X=15.2

Therefore the two numbers are 7.8 & 15.2

5 0
2 years ago
A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated fro
Veronika [31]

Answer:

There is no sufficient evidence to reject the company's claim at the significance level of 0.05

Step-by-step explanation:

Let \mu be the true mean weight per apple the company ship.  We want to test the next hypothesis

H_{0}:\mu=120 vs H_{1}:\mu\neq 120 (two-tailed test).

Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by

Z=\frac{\bar{X}-120}{\sigma/\sqrt{n}} which is normally distributed. The observed value is  

z_{0}=\frac{122.5-120}{12/\sqrt{49}}=1.4583. The rejection region for \alpha = 0.05 is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.

5 0
3 years ago
Help: I am a number between 60 and 100. My ones digit is six less than my tens digit. I am a prime number.
Reptile [31]

Answer:

Let's name the digit:

x- ones digit

y - tens digit

we know that x=y-2.

Now, y can be 6,7,8,9 (the number is between 60 and 100 (so depending on your understanding of "between", 0 is also possible. but then the number would have to have -2 as its ones digit, so in any case, it's not possible).

So the possibilities with x=y-2:

64

75

86

97

Out of those 64 and 86 are even, so they can't be prime.

75 has 5 in its ones number: it's divisible by 5.

so the correct answer is 97.

Step-by-step explanation:

Hope this helps!

5 0
3 years ago
Read 2 more answers
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