Using function concepts, it is found that:
- a) The y-intercept is y = 2.5.
- b) The horizontal asymptote is x = 3.
- c) The function is decreasing.
- d) The domain is
and the range is
. - e) The graph is given at the end of the answer.
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The given function is:
![g(x) = 3 - 8\left(\frac{1}{4}\right)^{2-x}](https://tex.z-dn.net/?f=g%28x%29%20%3D%203%20-%208%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B2-x%7D)
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Question a:
The y-intercept is g(0), thus:
![g(0) = 3 - 8\left(\frac{1}{4}\right)^{2-0} = 3 - 8\left(\frac{1}{4}\right)^{2} = 3 - \frac{8}{16} = 3 - 0.5 = 2.5](https://tex.z-dn.net/?f=g%280%29%20%3D%203%20-%208%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B2-0%7D%20%3D%203%20-%208%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B2%7D%20%3D%203%20-%20%5Cfrac%7B8%7D%7B16%7D%20%3D%203%20-%200.5%20%3D%202.5)
The y-intercept is y = 2.5.
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Question b:
The horizontal asymptote is the limit of the function when x goes to infinity, if it exists.
![\lim_{x \rightarrow -\infty} g(x) = \lim_{x \rightarrow -\infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2+\infty} = 3 - 8\left(\frac{1}{4}\right)^{\infty} = 3 - 8\frac{1^{\infty}}{4^{\infty}} = 3 -0 = 3](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Crightarrow%20-%5Cinfty%7D%20g%28x%29%20%3D%20%5Clim_%7Bx%20%5Crightarrow%20-%5Cinfty%7D%203%20-%208%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B2-x%7D%20%3D%203%20-%208%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B2%2B%5Cinfty%7D%20%3D%203%20-%208%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B%5Cinfty%7D%20%3D%203%20-%208%5Cfrac%7B1%5E%7B%5Cinfty%7D%7D%7B4%5E%7B%5Cinfty%7D%7D%20%3D%203%20-0%20%3D%203)
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![\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} 3 - 8\left(\frac{1}{4}\right)^{2-x} = 3 - 8\left(\frac{1}{4}\right)^{2-\infty} = 3 - 8\left(\frac{1}{4}\right)^{-\infty} = 3 - 8\times 4^{\infty} = 3 - \infty = -\infty](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Crightarrow%20%5Cinfty%7D%20g%28x%29%20%3D%20%5Clim_%7Bx%20%5Crightarrow%20%5Cinfty%7D%203%20-%208%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B2-x%7D%20%3D%203%20-%208%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B2-%5Cinfty%7D%20%3D%203%20-%208%5Cleft%28%5Cfrac%7B1%7D%7B4%7D%5Cright%29%5E%7B-%5Cinfty%7D%20%3D%203%20-%208%5Ctimes%204%5E%7B%5Cinfty%7D%20%3D%203%20-%20%5Cinfty%20%3D%20-%5Cinfty)
Thus, the horizontal asymptote is x = 3.
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Question c:
The limit of x going to infinity of the function is negative infinity, which means that the function is decreasing.
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Question d:
- Exponential function has no restrictions in the domain, so it is all real values, that is
. - From the limits in item c, the range is:
![(-\infty,3)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C3%29)
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The sketching of the graph is given appended at the end of this answer.
A similar problem is given at brainly.com/question/16533631
Answer: (a) P(no A) = 0.935
(b) P(A and B and C) = 0.0005
(c) P(D or F) = 0.379
(d) P(A or B) = 0.31
Step-by-step explanation: <u>Pareto</u> <u>Chart</u> demonstrates a relationship between two quantities, in a way that a relative change in one results in a change in the other.
The Pareto chart below shows the number of people and which category they qualified each public school.
(a) The probability of a person not giving an A is the difference between total probability (1) and probability of giving an A:
P(no A) = ![1-\frac{68}{1052}](https://tex.z-dn.net/?f=1-%5Cfrac%7B68%7D%7B1052%7D)
P(no A) = 1 - 0.065
P(no A) = 0.935
b) Probability of a grade better than D, is the product of the probabilities of an A, an B and an C:
P(A and B and C) = ![(\frac{68}{1052})(\frac{258}{1052})(\frac{327}{1052})](https://tex.z-dn.net/?f=%28%5Cfrac%7B68%7D%7B1052%7D%29%28%5Cfrac%7B258%7D%7B1052%7D%29%28%5Cfrac%7B327%7D%7B1052%7D%29)
P(A and B and C) = ![\frac{5736888}{1164252608}](https://tex.z-dn.net/?f=%5Cfrac%7B5736888%7D%7B1164252608%7D)
P(A and B and C) = 0.0005
c) Probability of an D or an F is the sum of probabilities of an D and of an F:
P(D or F) = ![\frac{269}{1052} +\frac{130}{1052}](https://tex.z-dn.net/?f=%5Cfrac%7B269%7D%7B1052%7D%20%2B%5Cfrac%7B130%7D%7B1052%7D)
P(D or F) = ![\frac{399}{1052}](https://tex.z-dn.net/?f=%5Cfrac%7B399%7D%7B1052%7D)
P(D or F) = 0.379
d) Probability of an A or B is also the sum of probabilities of an A and of an B:
P(A or B) = ![\frac{68}{1052} +\frac{258}{1052}](https://tex.z-dn.net/?f=%5Cfrac%7B68%7D%7B1052%7D%20%2B%5Cfrac%7B258%7D%7B1052%7D)
P(A or B) = ![\frac{326}{1052}](https://tex.z-dn.net/?f=%5Cfrac%7B326%7D%7B1052%7D)
P(A or B) = 0.31
15/24 = 5/8
15 hours out of 24 hours.!!!!
5/8 of a day, or 0.625 as a decimal.
in minutes, it's 900/1,440
Hope this helps!!!!!
Answer:
A
Step-by-step explanation:
An educated guess because I really forgot how to do these
Answer: B plz mark me bralny
Step-by-step explanation: