All categories

3 years ago

Solve each of the following equations. |3x−4(x+1)|=2

Mathematics

1 answer:

kramer3 years ago

7 0

Answer:

-2, -6

Step-by-step explanation:

|3x−4(x+1)|=2

|3x - 4x - 4| = 2

|-x - 4| = 2

-x - 4 = 2

-x = 6

x = -6

-x - 4 = -2

-x = 2

x = -2

You might be interested in

Find an upper limit for the zeroes 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0

erik [133]

<u>Answer-</u>

2 is the upper limit for the zeros.

<u>Solution-</u>

The given function f(x) is,

$2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

For calculating the zeros,

$\Rightarrow f(x)=0$

$\Rightarrow 2x^4 -7x^3 + 4x^2 + 7x - 6 = 0$

$\Rightarrow 2x^4-4x^3-3x^3+6x^2-2x^2+ 4x+3x-6=0$

$\Rightarrow 2x^3(x-2)-3x^2(x-2)-2x(x-2)+3(x-2)=0$

$\Rightarrow (x-2)(2x^3-3x^2-2x+3)=0$

$\Rightarrow (x-2)(x^2(2x-3)-1(2x-3))=0$

$\Rightarrow (x-2)(x^2-1)(2x-3)=0$

$\Rightarrow (x-2)(x+1)(x-1)(2x-3)=0$

$\Rightarrow x-2=0,\ x+1=0,\ x-1=0,\ 2x-3=0$

$\Rightarrow x=2,\ x=-1,\ x=1,\ x=\frac{3}{2}$

From all the 4 roots, it can be obtained that 2 is the greatest zero.

7 0

3 years ago

10 POINTS AND WILL GIVE BRAINLIEST

Vladimir [108]

${3}^{ - 2x} = { (\frac{1}{ {3}^{2} } )}^{x} = ( { \frac{1}{9} )}^{x} an \\ exponential \: function \: of \: the \: form \\ f(x) = a \times {b}^{x} \: with \: a \: = 1 \: and \\ b = \frac{1}{9}$

8 0

3 years ago

How do you solve 5x - 5y = ?

Softa [21]

Answer:

X=Y

Step-by-step explanation:

5x-5Y=

+5y=5y

5x=5y

divide both sides by 5

x=y

8 0

3 years ago

PLSSSSSSS HURRRY

Dennis_Churaev [7]

Answer:

1. 3/5=15m

2. 3/5m=15

3. 3/5+m=15

4. 3/5m=15

5. 3/5/m=15

7 0

3 years ago

Read 2 more answers

17 friends to 18 friends (round to the nearest percent)

konstantin123 [22]

Answer:

5.88%

Step-by-step explanation:

18 - 17 / 17

1/17 = 0.0588

= 5.88%

7 0

2 years ago