2 years ago

Find the missing length. The triangles in each pair are similar?

Mathematics

1 answer:

larisa [96]2 years ago

7 0

Answer:

The length of the missing side is 117 :)

Step-by-step explanation:

I set up a proportion using sides NM, LD, LN, and DC :

182/28 = x/18

182(18) = 28x

3276 = 28x

3276/28 = 28x/28

x = 117

You might be interested in

Simplify Fraction improper 13/8

Soloha48 [4]

Answer:

Exact Form:

13 /8

Decimal Form:

1.625

Mixed Number Form:

1 5/ 8

8 0

2 years ago

The base of a cab in New York is $2.50 as soon as you enter the cab. There is an additional charge of $2.50 per mile traveled. C

Anastaziya [24]

Answer:

7 miles

Step-by-step explanation:

3 0

3 years ago

(-5b^3) (-3b^6)<br><br> Solve the equation

3241004551 [841]

Answer: 15b^9

Explanation:

-5*-3=15

b^3*b^6=b^9

3 0

2 years ago

Aaaaaaaaahahahahahqq What’s the answer?

Svetllana [295]

Answer:

2.5

Step-by-step explanation:

-2+5 equals 3-8= -5 divided by 2 equals -2.5

Second DUDE YOU NEED TO CHILL-ANYBODY WHO SEES THIS-RATE THIS FIVE STARS IF YOU THINK THIS GUY NEEDS TO CHILL!!!

8 0

3 years ago

What is the area (in square units) of the region under the curve of the function f(x)=x+3, on the interval from x=1 to x=3 ?

aleksandrvk [35]

Answer:

10 square units

Step-by-step explanation:

We want to find the area under the curve $f(x)=x+3$ from x=1 to x=3.

We use definite integrals to find this area.

$\int\limits^3_1 {x+3} \, dx$

We integrate to obtain:

$\frac{x^2}{2}+3x|_1^3$

We evaluate the limits to get:

$\frac{3^2}{2}+3(3)-(\frac{1^2}{2}+3(1))$

$4.5+9-0.5-3=10$

Therefore the area under the curve from x=1 to x=3 is 10 square unit.

8 0

3 years ago