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sergejj [24]
3 years ago
5

The chart shows what method of transportation students at local high school use to get to school. The results are given by grade

level.
What is the probability that a student rides the bus given that they are in the 10th grade?

Mathematics
1 answer:
kogti [31]3 years ago
8 0
The ride bus says 150
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Write a few sentences that could represent this math problem.
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Please help me with the following!
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D. 2040

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2 years ago
A box contains 5 red and 5 blue marbles. Two marbles are withdrawn randomly. If they are the same color, then you win $1.10; if
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Answer:

a) The expected value is \frac{-1}{15}

b) The variance is  \frac{49}{45}

Step-by-step explanation:

We can assume that both marbles are withdrawn at the same time. We will define the probability as follows

#events of interest/total number of events.

We have 10 marbles in total. The number of different ways in which we can withdrawn 2 marbles out of 10 is \binom{10}{2}.

Consider the case in which we choose two of the same color. That is, out of 5, we pick 2. The different ways of choosing 2 out of 5 is \binom{5}{2}. Since we have 2 colors, we can either choose 2 of them blue or 2 of the red, so the total number of ways of choosing is just the double.

Consider the case in which we choose one of each color. Then, out of 5 we pick 1. So, the total number of ways in which we pick 1 of each color is \binom{5}{1}\cdot \binom{5}{1}. So, we define the following probabilities.

Probability of winning: \frac{2\binom{5}{2}}{\binom{10}{2}}= \frac{4}{9}

Probability of losing \frac{(\binom{5}{1})^2}{\binom{10}{2}}\frac{5}{9}

Let X be the expected value of the amount you can win. Then,

E(X) = 1.10*probability of winning - 1 probability of losing =1.10\cdot  \frac{4}{9}-\frac{5}{9}=\frac{-1}{15}

Consider the expected value of the square of the amount you can win, Then

E(X^2) = (1.10^2)*probability of winning + probability of losing =1.10^2\cdot  \frac{4}{9}+\frac{5}{9}=\frac{82}{75}

We will use the following formula

Var(X) = E(X^2)-E(X)^2

Thus

Var(X) = \frac{82}{75}-(\frac{-1}{15})^2 = \frac{49}{45}

7 0
3 years ago
Assume standard deviation of all invoices is $200. Sample 100 invoices. What is the standard deviation of xbar
posledela

Answer:

<h3>20</h3>

Step-by-step explanation:

Standard deviation of the mean is expressed as:

SM = s/√n

s is the standard deviation of all invoices

n is the sample size of the invoiced

Given

s = $200

n = 100

Required

Standard deviation of the mean

Substitute the given parameters into the given equation

SM = 200/√100

SM = 200/10

SM = 20

Hence the standard deviation of xbar is 20

3 0
3 years ago
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