Answer:
HEY ...ANDREW I'M ARGHYA INDIAN HERE CAN YOU BE MIE FREIND...??
BCD = 38
ECF = 180
DCF = 38
HOPE ITS HELP YOU
Is the 10 taking away 5 or was it meant to me 10.5 ?
Answer:
cos(∅) = 3/5
Step-by-step explanation:
cos(∅) = adjacent/hypotenuse
We don't know what the hypotenuse is so we gotta use Pythagorean theorem to find it.
a² + b² = c²
4² + 3² = c²
√(4² + 3²) = c
c = 5 , this is our hypotenus
cos(∅) = adjacent/hypotenuse
cos(∅) = 3/5
To get the z-value of the scores of the four students, we are going to use the formula for standard score or z-score. It is score minus the mean score, then divided by standard deviation.
z= Score (X)-Mean / SD
To find the z-value of each score, we have to use a Z table. Using the z-score, we are to look first at the y-axis of the table which will highlight the first two digits of the z-score. Then, the x-axis for the second decimal place of the z-score.
You can use this as reference for the z-table: http://www.stat.ufl.edu/~athienit/Tables/Ztable.pdf
Mean= 500SD= 100Scores= 560, 450, 640, 530
For the student who scored 560,z= X-Mean / SDz= 560-500 / 100z= 60 / 100z= 0.6
The score is 0.6 standard deviation above the mean. The z-value is 0.7257 or 72.57%.
For the student who scored 450,z= X-Mean / SDz= 450-500 / 100z= -50 / 100z= -0.5
The score is -0.5 standard deviation above the mean. The z-value is 0.3085 or 30.85%.
For the student who scored 640,z= X-Mean / SDz= 640-500 / 100z= 140 / 100z= 1.4
The score is 1.4 standard deviation above the mean. The z-value is 0.9192 or 91.92%.
For the student who scored 530,z= X-Mean / SDz= 530-500 / 100z= 30 / 100z= 0.3
The score is 0.3 standard deviation above the mean. The z-value is 0.6179 or 61.79%.
Answer:
The median and IQR are better statistical measures when a data set has outliers. Using the median, you can infer that the home prices for Cinnamon Court are higher than those of Pepper Hill Road. Using the IQR you can infer that home prices on Cinnamon Court are less variable than on Pepper Hill.
Step-by-step explanation:
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