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worty [1.4K]
3 years ago
12

Need answers!! Will give 20 pts. !!

Mathematics
1 answer:
devlian [24]3 years ago
4 0
1. 64=8
2. 361=19
3. 471969=687
4. 0.0676=.26
5. .0025=0.5
6. 25/36=.83...

1. 438=20.92
2. 813=28.51
3. 958=30.95
4. 218.1529=14.77
5. .235=.48
6. 3.8809=1.97

1. positive numbers have 2 square roots, one positive & one negative

1.-268=16.3
2.-79=9(8.8...)
3.-0.102=.31

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What is the measure of JM?
Ray Of Light [21]

Answer:

10???

Step-by-step explanation:

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3 years ago
Find the measures of the numbered angles in rhombus QRST.
weeeeeb [17]
1)90, 2)47, 3)43, 4)47
8 0
2 years ago
Joey has a full 40 coins consisting of only quarters and nickels if the total value is $5.00 how many of each does joey have.
Archy [21]
Q + n = 40....q = 40 - n
0.25q + 0.05n = 5

0.25(40 - n) + 0.05n = 5
10 - 0.25n + 0.05n = 5
-0.25n + 0.05n = 5 - 10
 - 0.20n = -5
n = -5 / -0.20
n = 25 <=== 25 nickels

q + n = 40
q + 25 = 40
q = 40 - 25
q = 15 <== 15 quarters
7 0
3 years ago
Read 2 more answers
Please help and explain process too. Thank you!! ​
sergey [27]
The answer is x^2+2x-5

7 0
3 years ago
A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at
valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

Red = 5

White = 6

Black = 9

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

Total = 5 + 6 + 9

Total = 20

This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

4 0
3 years ago
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