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yanalaym [24]
3 years ago
7

Solve 2sin x + sqrt3 = 0

Mathematics
1 answer:
Natasha2012 [34]3 years ago
5 0
Subtract sqrt 3 to isolate 2sin x
Divide by 2 to isolate sin x
Take the arcsin of each side to isolate x
Thinking of a 30-60-90 triangle, we know that x sqrt 3 is opposite 60° and 2x acts as the hypotenuse, thus it will be some variation of 60°.
 In order to produce a negative result, x must be -60° (-π/3)
It is worth noting that this is a restricted value. Any addition/subtraction of 2π from this answer will produce the same result, thus your full answer is the above plus or minus 2kπ where k ∈ Z (k is an interger)

2\sin x+\sqrt{3}=0\\\\2\sin x=-\sqrt{3}\\\\\sin x=-\frac{\sqrt{3}}2\\\\\sin^{-1}(\frac{\sqrt{3}}2)=x\\\\\boxed{x=-\frac{\pi}3\pm2k\pi,\ k\in \mathbb{Z}}\ (-\frac{\pi}3=-60\°)




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Answer:

her first mistake was on line 3.

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line 3: 80 + 10

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Step-by-step explanation:

on line 3 she added 80 + 2, but she should have multiplied 2 by 5. the correct steps would be:

line 1: 80 + [2(3 1/2 + 1 1/2)]

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3 years ago
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4 0
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const2013 [10]

Answer:

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Finding calculations using exponents will help,

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