C is the answer to the problem
The answer is 0.91 because it is
Answer:
We conclude that the equivalent expression is:
![3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)=6x+20y+8z](https://tex.z-dn.net/?f=3%5Cleft%282x%5Cright%29%2B4y%5Cleft%285%5Cright%29%2B%5Cleft%284%5Ctimes%20%5C%3A2z%5Cright%29%3D6x%2B20y%2B8z)
Step-by-step explanation:
Given the expression
![3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)](https://tex.z-dn.net/?f=3%5Cleft%282x%5Cright%29%2B4y%5Cleft%285%5Cright%29%2B%5Cleft%284%5Ctimes%20%5C%3A2z%5Cright%29)
Remove parentheses: (a) = a
![=3\times \:2x+4\times \:5y+4\times \:2z](https://tex.z-dn.net/?f=%3D3%5Ctimes%20%5C%3A2x%2B4%5Ctimes%20%5C%3A5y%2B4%5Ctimes%20%5C%3A2z)
Multiply the numbers: 3 × 2 = 6
![=6x+4\times \:5y+4\times \:2z](https://tex.z-dn.net/?f=%3D6x%2B4%5Ctimes%20%5C%3A5y%2B4%5Ctimes%20%5C%3A2z)
Multiply the numbers: 4 × 5 = 20
![=6x+20y+4\times \:2z](https://tex.z-dn.net/?f=%3D6x%2B20y%2B4%5Ctimes%20%5C%3A2z)
Multiply the numbers: 4 × 2 = 8
![=6x+20y+8z](https://tex.z-dn.net/?f=%3D6x%2B20y%2B8z)
Thus, we conclude that the equivalent expression is:
![3\left(2x\right)+4y\left(5\right)+\left(4\times \:2z\right)=6x+20y+8z](https://tex.z-dn.net/?f=3%5Cleft%282x%5Cright%29%2B4y%5Cleft%285%5Cright%29%2B%5Cleft%284%5Ctimes%20%5C%3A2z%5Cright%29%3D6x%2B20y%2B8z)
Answer:
- North Middle School = 10 students
- Central Middle School = 6 students
- South Middle School = 4 students
Step-by-step explanation:
First calculate the total number of students in all the schools:
= 618 + 378 + 204
= 1,200 students
Use this number to calculate the proportion of the total population that a school so that this can then be used to determine the proportion of the 20 delegates they should sent.
North Middle school:
= 618/1,200 * 20
= 10 students
Central Middle School:
= 378 / 1,200 * 20
= 6 students
South Middle School:
= 204/1,200 * 20
= 4 students
9514 1404 393
Answer:
1.0 N
Step-by-step explanation:
When the length increases by the factor 120/80 = 3/2, the force required is multiplied by the inverse of this: 2/3.
The required force is ...
(2/3)(1.5 N) = 1.0 N