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Ksenya-84 [330]

3 years ago

12

Katarina bought a package of 500 stickers. Each sheet in the package has 20 stickers. 25% of the stickers on each sheet are hear

ts. The remaining stickers are stars. Drag the tiles to identify the number of heart stickers and the number of star stickers in the package. Numbers may be used once or not at all.

2 answers:

olga2289 [7]3 years ago

6 0

Answer:125 hearts 375 stars

Step-by-step explanation:

puteri [66]3 years ago

5 0

Answer:

100 are stars

Step-by-step explanation:

25% divided by 100 equals 0.25

0.25 times 20 equals 5

500 divided by 5 equals 100

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Wewaii [24]

Answer:

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Step-by-step explanation:

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3 years ago

A store sells 2 1/2 pounds of shrimp for $18. What is the unit price of the shrimp? Explain Plz

krok68 [10]

2 1/2 pounds = $18
for 1 pound = How many dollars

1 pound = $18 ÷ 2 1 /2
= 18 ÷ 2.5
= $ 7.2

1 pound = 453.6 grams
so 453.6 grams = $7.2

price of 1 gram = 7.2 / 453.6 = $ 0.0158

4 0

4 years ago

Find the area of a trapezoid with base lengths 3 and 5 and heigh of 9

Likurg_2 [28]

A <u>trapezoid</u> is a quadrilateral with exactly one pair of parallel sides.

Formula for area: $A = \frac{1}{2}(^{b}1 + ^{b}2)(h)$

In this formula, the bases are the parallel sides.

Now plug the information into the formula.

$A = \frac{1}{2} (3 + 5)(9)$ .

Follow your order of operations, simplify inside the parentheses first.

$A = \frac{1}{2}(8)(9)$ .

(1/2)(8) is 4 so we have (4)(9) which is 36.

So the area of the trapezoid is 36.

7 0

4 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

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4 years ago

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Hoochie [10]

Answer:idk so your not getting it either

Step-by-step explanation:

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3 years ago