Question

Find the area of a trapezoid with base lengths 3 and 5 and heigh of 9

Answer 1

A trapezoid is a quadrilateral with exactly one pair of parallel sides.

Formula for area: $A = \frac{1}{2}(^{b}1 + ^{b}2)(h)$

In this formula, the bases are the parallel sides.

Now plug the information into the formula.

$A = \frac{1}{2} (3 + 5)(9)$.

Follow your order of operations, simplify inside the parentheses first.

$A = \frac{1}{2}(8)(9)$.

(1/2)(8) is 4 so we have (4)(9) which is 36.

So the area of the trapezoid is 36.