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Svet_ta [14]
3 years ago
6

Alicia bought 4 T-shirts for $23.00. Using the unit rate, how much would 6 T-shirts cost?

Mathematics
1 answer:
LekaFEV [45]3 years ago
3 0

i think that you would just take 23/4=$5.75

so take 6 times 5.75 and you should get $34.5

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The area of a rectangular wall of a barn is 108 square feet. Its length is 12 feet longer than the width. Find the length and wi
forsale [732]
Area = Width x Length
Area = 108
Square root of 108 = 10.4

108/ 9 = 12      ...12 is not 12 larger than 9
108/ 6 = 18      ...18 is 12 larger than 6

108 = 6 x 18

Width = 6
Length = 18
8 0
3 years ago
If f(x) = 2x2 +
Pavel [41]

Answer:

f(x + 1) = 2x² + 4x + 5

Step-by-step explanation:

Step 1: Plug in (x + 1) in as <em>x</em> in f(x)

f(x + 1) = 2(x + 1)² + 3

Step 2: Expand and distribute

f(x + 1) = 2(x² + 2x + 1) + 3

f(x + 1) = 2x² + 4x + 2 + 3

f(x + 1) = 2x² + 4x + 5

3 0
4 years ago
Find the volume of the cylinder.
Ivanshal [37]

Answer:

48π

Step-by-step explanation:

Volume of cylinder = πr^2l

3 0
3 years ago
Read 2 more answers
Multiple-Choice Integration, Picture Included, Please Include Work
ValentinkaMS [17]
\displaystyle\int_0^2\sqrt{4-x^2}\,\mathrm dx

Recall that a circle of radius 2 centered at the origin has equation

x^2+y^2=4\implies y=\pm\sqrt{4-x^2}

where the positive root gives the top half of the circle in the x-y plane. The definite integral corresponds to the area of the right half of this top half. Since the area of a circle with radius r is \pi r^2, it follows that the area of a quarter-circle would be \dfrac{\pi r^2}4.

You have r=2, so the definite integral is equal to \dfrac{2^2\pi}4=\pi.

Another way to verify this is to actually compute the integral. Let x=2\sin u, so that \mathrm dx=2\cos u\,\mathrm du. Now

\displaystyle\int_0^2\sqrt{4-x^2}\,\mathrm dx=\int_0^{\pi/2}\sqrt{4-(2\sin u)^2}(2\cos u)\,\mathrm du=4\int_0^{\pi/2}\cos^2u\,\mathrm du

Recall the half-angle identity for cosine:

\cos^2u=\dfrac{1+\cos2u}2

This means the integral is equivalent to

\displaystyle2\int_0^{\pi/2}(1+\cos 2u)\,\mathrm du=2u+\sin2u\bigg|_{u=0}^{u=\pi/2}=\pi
4 0
3 years ago
Write the quadratic equation whose roots are -2 and 1, and whose leading coefficient is 4 .
Kaylis [27]

Answer: the equation is

4x^2 + 4x - 12

Step-by-step explanation:

A quadratic equation is an equation in which the highest power of the unknown is 2.

The general form of a quadratic equation is expressed as

ax^2 + bx + c

Where

a is the leading coefficient

c is a constant

Assuming we want to write the quadratic equation in x, from the information given, the roots which are given are -2 and 1 and the leading coefficient is 4.

Therefore, the linear factors of the quadratic equation will be (x+2) and (x-1)

the equation becomes

(x+2)(x-1)

= x^2 - x +2x - 3

= x^2 + x - 3

Given a leading coefficient of 4, we will multiply the quadratic expression by 4. It becomes

4(x^2 + x - 3)

= 4x^2 + 4x - 12

7 0
3 years ago
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