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3 years ago

Which value of c would make the following express completely factored? 8x+cy

2 answers:

6 0

The answer is B, 7.

$\sf 8x+2y$

We can factor a 2 out of this: $\sf 2(4x+y)$

$\boxed{\sf 8x+7y}$

We can't factor anything.

$\sf 8x+12y$

We can factor a 4 out of this: $\sf 4(2x+3y)$

$\sf 8x+16y$

We can factor an 8 out of this: $\sf 8(x+2y)$

So your answer is B, 7.

GaryK [48]3 years ago

3 0

Answer:

b on edge

Step-by-step explanation:

just took the test

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GREYUIT [131]

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2 years ago

the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const

laiz [17]

In general, the volume

$V=\pi r^2h$

has total derivative

$\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)$

If the cylinder's height is kept constant, then $\dfrac{\mathrm dh}{\mathrm dt}=0$ and we have

$\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}$

which is to say, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ are directly proportional by a factor equivalent to the lateral surface area of the cylinder ( $2\pi r h$ ).

Meanwhile, if the cylinder's radius is kept fixed, then

$\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}$

since $\dfrac{\mathrm dr}{\mathrm dt}=0$ . In other words, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dh}{\mathrm dt}$ are directly proportional by a factor of the surface area of the cylinder's circular face ( $\pi r^2$ ).

Finally, the general case ( $r$ and $h$ not constant), you can see from the total derivative that $\dfrac{\mathrm dV}{\mathrm dt}$ is affected by both $\dfrac{\mathrm dh}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ in combination.

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2 years ago

A student concludes that the solution to the equation ( 2×+1+3=0 is×=4

Slav-nsk [51]

Answer:

x = -2

Step-by-step explanation:

2x + 1 + 3 = 0

2x + 4 = 0

x = -2

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2 years ago

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Vesnalui [34]

Just add it all together plus multiply

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3 years ago