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xenn [34]
3 years ago
12

Which value of c would make the following express completely factored? 8x+cy

Mathematics
2 answers:
Artist 52 [7]3 years ago
6 0
The answer is B, 7.

\sf 8x+2y

We can factor a 2 out of this: \sf 2(4x+y)

\boxed{\sf 8x+7y}

We can't factor anything.

\sf 8x+12y

We can factor a 4 out of this: \sf 4(2x+3y)

\sf 8x+16y

We can factor an 8 out of this: \sf 8(x+2y)

So your answer is B, 7.
GaryK [48]3 years ago
3 0

Answer:

b on edge

Step-by-step explanation:

just took the test

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What is 1,200 x 1,300
rewona [7]

Answer:

It's 1,560,000

Step-by-step explanation:

You can just put it into a calculator.

5 0
2 years ago
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a water balloon is tossed into the air with an upward velocity of 25 ft/s its height h(t) in ft after t seconds is given by the
Montano1993 [528]
When the height is 0 that is when it hits the ground
solve
0=-16t²+25x+3
cant factor so use quadratic formula

for
0=ax²+bx+c
x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}

so for
0=-16t²+25t+3
a=-16
b=25
c=3
so

x=\frac{-25+/-\sqrt{25^2-4(-16)(3)}}{2(-16)}
x=\frac{-25+/-\frac{625+192}}{-32}
x=\frac{-25+/-\frac{817}}{-32}
it has to be a positive time

so it will hit the ground after \frac{25+\sqrt{817}}{32} seconds
4 0
3 years ago
Three increased by the quotient of six and a number
GuDViN [60]

"Increased" means to add.

"Quotient" is a total of a division problem.

"A number" means the unknown.

This is our problem: 3 + 6 / N

8 0
3 years ago
Read 2 more answers
Justin is constructing a line through point Q that is perpendicular to line n. He has already constructed the arcs shown. He pla
krek1111 [17]
<span>B. It must be the same as when he constructed the arc centered at point A. This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined. Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing. "... places his compass on point B ..." Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense. A .It must be wider than when he constructed the arc centered at point A. Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer. B It must be the same as when he constructed the arc centered at point A. Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer. C. It must be equal to BQ. Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong. D.It must be equal to AB. Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.</span>
8 0
3 years ago
Read 2 more answers
P-3 1/5=7 1/3 I need help​
alekssr [168]

We have:

p-3\frac{1}{5} =7\frac{1}{3}  => p=7\frac{1}{3}+3\frac{1}{5}= 10\frac{8}{15}

ok done. Thank to me :>

7 0
2 years ago
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