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3 years ago

What is the value of exterior angle?

Mathematics

1 answer:

charle [14.2K]3 years ago

5 0

Answer:

this a good question someone reply when its answered

Step-by-step explanation:

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A man stands on a balcony 140 feet up and sees a bus stop at a 75 degree angle How far is the bus stop to the man in nearest fee

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<span>to any object given his angle of sight theta.
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Nuetrik [128]

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ASAP PLEASE ANSWER quadrilateral ABCD is dilated at center (0,0) with scale factor 1/2 to form quadrilateral A'B'C'D'. wha is th

zhenek [66]

Answer:

$|A'B'|=\sqrt{5}$

Step-by-step explanation:

The points A and B have coordinates at (0,4) and (4,2) respectively.

The distance formula can be used to find the length of AB.

$|AB|=\sqrt{(4-0)^2+(2-4)^2}$

$|AB|=\sqrt{(4)^2+(-2)^2}$

$|AB|=\sqrt{16+4}$

$|AB|=\sqrt{20}$

$|AB|=2\sqrt{5}$

Since quadrilateral ABCD was enlarged with a scale factor of $\frac{1}{2}$ .

The length of A'B' is

$\frac{1}{2}|AB|$

$=\frac{1}{2}\times2\sqrt{5}$

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What is the exponential regression equation that fits these data x=-4 y=0.25

Galina-37 [17]

Answer: is y = 3.80 • 2.01^x

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3 years ago

Find the angle between the given vectors to the nearest tenth of a degree.

saul85 [17]

Answer:

Step-by-step explanation:

Given

u = <6, -1>

u = 6i-j

and

v=<7,-4>

v=7i-4j

The formula for angle is:

Let x be the angle

$cos\ x = \frac{u.v}{||u||.||v||}$

where ||u|| is the length and u.v is the dot product or scalar product of both vectors

So,

$||u|| = \sqrt{(6)^2+(-1)^2}\\ = \sqrt{36+1}\\ = \sqrt{37}\\ ||v||=\sqrt{(7)^2+(-4)^2}\\ = \sqrt{49+16}\\ = \sqrt{65}\\$

$u.v = u_1u_2+v_1v_2\\= (6)(7)+(-1)(-4)\\=42+4\\=46$

$cos\ x=\frac{46}{\sqrt{37}\sqrt{65}} \\= \frac{46}{\sqrt{2405} }\\Can\ also\ be\ written\ as:\\= \frac{46}{\sqrt{2405} } * \frac{\sqrt{2405} }{\sqrt{2405}} \\=\frac{46\sqrt{2405} }{2405}$

The calculated angle will be in radians. To find the angle in degrees:

$x = \frac{180}{\pi} cos^{-1} (\frac{46\sqrt{2405} }{2405})\\x = 20.282\\x= 20.3\\$

Hence Option A is correct ..

6 0

4 years ago