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4 years ago

X -y =-4 -2x + 3y = 6

Mathematics

1 answer:

hoa [83]4 years ago

8 0

Answer:

y=-2

x=-6

Idk if it's right

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Answer:

Solution given:

A.coordinate are

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B(0,-3)

C(4,5)

B.Each length are :

we have

length $\sqrt{(x2-x1)²+(y2-y1)²}$

now

AB: $\sqrt{(-2-0)²+(3+3)²}$ = $2\sqrt{10}$ units

BC: $\sqrt{(0-4)²+(-3-5)²}$ = $4\sqrt{5}$ units

AC: $\sqrt{(-2-4)²+(3-5)²}$ = $2\sqrt{10}$ units

C. the figure:

By using Pythagoras law

base[b]=AB=perpendicular [p]=AC

hypotenuse [h]=BC

we have

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substituting value

( $4\sqrt{5}$ )²=2p²

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80=2*4*10

80=80

SO IT IS RIGHT ANGLED ISOSCELES TRIANGLE.

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3 years ago

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4 years ago

A quadratic equation of the form 0=ax^2+bx+c has a discriminant value of -16. How many real numbers solutions does the equation

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3 years ago

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