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jek_recluse [69]
3 years ago
6

Can some one please help me will give 94 points for it

Mathematics
2 answers:
NNADVOKAT [17]3 years ago
7 0
You can solve this by using "similar triangles".

In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.

You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:
\frac{AC}{BC} =  \frac{DF}{EF}
Substitute for the values of AC, BC, DF and EF:
\frac{x}{4}  =  \frac{11}{8}  \\  \\ 8x = 4 \times 11 \\  \\ x =  \frac{44}{8}
x = 5.5 \: units
To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.
\frac{AB}{BC}  =  \frac{DE}{EF}
Substitute for the values and solve:
\frac{3}{4}  =  \frac{y}{8}
4y = 24 \\  \\ y = 6 \: units

We have the value x to be 5.5 units and y to be 6 units.

Step2247 [10]3 years ago
3 0

Answer:

x = 5.5

y = 6

Step-by-step explanation:

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Step-by-step explanation:

If we assume that DC is parallel to AB, then triangle DOC is similar to triangle AOB.

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DO / (DO + 20) = CO / (CO + 24)

Edit: OD is 2 cm shorter than OC.  If we call x the length of OD, then the length of OC is x+2.

Putting this into our proportion:

x / (x + 20) = (x + 2) / (x + 2 + 24)

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Cross multiply:

x (x + 26) = (x + 2) (x + 20)

Distribute:

x² + 26x = x² + 20x + 2x + 40

x² + 26x = x² + 22x + 40

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x = 10

So the length of DO is 10 cm.

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