Can some one please help me will give 94 points for it
2 answers:
You can solve this by using "similar triangles".
In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.
You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:
Substitute for the values of AC, BC, DF and EF:
To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.
Substitute for the values and solve:
We have the value x to be 5.5 units and y to be 6 units.
In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.
You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:
Substitute for the values of AC, BC, DF and EF:
To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.
Substitute for the values and solve:
We have the value x to be 5.5 units and y to be 6 units.
You might be interested in
This solution to this problem is predicated on the fact that the circumference is just: . A straight line going through the center of the garden would actually be the diameter, which is well known to be two times the radius of the circle, so we can say that the circumference is just:
So, solving for both the radius and the diameter gives us:
So, the length of thes traight path that goes through the center of the guardain is just , and we can use the radius for the next part of the problem.
The area of a circle is , which means we can just plug in the radius and find our area:
So, we have found our area() and the problem is done.