The plants that use photosynthesis would die because the plants would not create food. They would die of hunger. Without another source of food, most of the animals would likewise die off to.
Answer:
In terms of adaptation, fitness refers to the ability of an organism to survive and reproduce in a constantly changing environment.
Adaptive traits are very much important in a constantly changing environment as they increase the chances of survival of a population in the environment.
For example, Darwin's finches adapted to develop different types of beaks in order to get nutrition in different environments. Long necks of giraffes are also considered as a result of adaptation which helps them get the food located high on trees.
Answer:
Groups 4 to 7 are most likely to be undergoing the mitotic phase of the cell cycle.
Explanation:
Since the four proteins used p16, p18, p21, and p27 are inhibitors of cyclin-dependent kinases (CDK), their absence indicates that the cell is undergoing mitosis - the cell cycle is regulated by CDKs. In the absence of these inhibitors, the cell cycle moves on forward. Because the bar for DNA replication is longer in the case for groups 4 to 7, it is indicative of the fact that these cells have gone through the mitotic phase.
Hope that answers the question, have a great day!
Answer:
In plants and algae, which developed much later, photosynthesis occurs in a specialized intracellular organelle—the chloroplast. Chloroplasts perform photosynthesis during the daylight hours. The immediate products of photosynthesis, NADPH and ATP, are used by the photosynthetic cells to produce many organic molecules.
Answer:
Let the "barred" allele be caller B and the "non-white" allele b. Since chickens use chromosomes 
and 
to determine sex, hens would have chromosomes 
, and roosters would have chromosomes 
. A Z-linked gene is represented as a superscript on the chromosome, 
for the dominant allele and 
for the ressesive allele.
A barred hen would have a copy of B on its Z chromosome, a non-barred rooster would have both copies of b on both Z chromosomes. Using Punnet squares to represent the crosses we get the following cases:
That is a ratio of two barred heterozygote roosters to two non-barred hens. Crossing them we get:
That is a ratio of one barred heterozygote rooster to one barred hen to one non-barred rooster to one non barred hen.
