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3 years ago

7

Kodi makes decorate custom cupcakes. She sells one dozen for $15.99. Shelley sell cupcakes for $14.99 more than the number of do

zens of cupcakes.

1 answer:

ValentinkaMS [17]3 years ago

8 0

You answer is 39.99$

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What is the measure of <1? (ON ALL THE PROBLEMS) And tell if 4 and 5 are right. ( d means degrees)

cestrela7 [59]

Answer:

The most common measure of an angle is in degrees. Here is a brief introduction to the four types of angles: Right angle. With this angle, you can never go wrong. The right angle is one of the most easily recognizable angles. It’s in the form of the letter L, and it makes a square corner (see Figure 2). It has a measure of 90 degrees.

Step-by-step explanation:

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3 years ago

I will give brainliest and 30 points

Oksi-84 [34.3K]

Answer: 15

Step-by-step explanation:

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3 years ago

Read 2 more answers

5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim

Ne4ueva [31]

Answer:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

$S_p=2.940$

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

$df=60+72-2=130$

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

$n_1 =60$ represent the sample size for people who used a self service

$n_2 =72$ represent the sample size for people who used a cashier

$\bar X_1 =5.2$ represent the sample mean for people who used a self service

$\bar X_2 =6.1$ represent the sample mean people who used a cashier

$s_1=3.1$ represent the sample standard deviation for people who used a self service

$s_2=2.8$ represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

And t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

System of hypothesis

Null hypothesis: $\mu_1 \geq \mu_2$

Alternative hypothesis: $\mu_1 < \mu_2$

This system is equivalent to:

Null hypothesis: $\mu_1 - \mu_2 \geq 0$

Alternative hypothesis: $\mu_1 -\mu_2 < 0$

We can find the pooled variance:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

And the deviation would be just the square root of the variance:

$S_p=2.940$

The statistic is given by:

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

The degrees of freedom are given by:

$df=60+72-2=130$

And now we can calculate the p value with:

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0

3 years ago

Seven-ninths of the pencils in a box are yellow. Three-tenths of the yellow pencils are sharpened. What fraction represents the

jek_recluse [69]

Answer:

7/30

Step-by-step explanation:

We are given that Seven-ninths (7/9) of the pencils in a box are yellow and three-tenths (3/10) of the yellow pencils are sharpened.

To find the fraction that represents sharpened yellow pencils, we find the product of the the fraction of yellow pencils and the fraction of yellow pencils that are sharpened.

That is:

=> (7 / 9) * (3 / 10)

=(7 * 3) / (9 * 10)

= 21 / 90

= 7 / 30

7/30 represents the fraction of sharpened yellow pencils.

3 0

4 years ago

Find the mean, the median, and all modes for the data in the given frequency distribution. (Round your answers to one decimal pl

kvasek [131]

Answer: Mean = 7.8

Median = 9

Mode = 2,9

Step-by-step explanation: <u>Mean</u> is the average value of a data set. Mean from a frequency table is calculated as:

$E(X)=\frac{2(10)+3(9)+9(10)+11(7)+12(3)+15(4)+16(3)}{10+9+10+7+3+4+3}$

E(X) = 7.8

Mean for the given frequency distribtuion is 7.8.

<u>Median</u> is the central term of a set of numbers. Median in a frequency table is calculated as:

1) Find total number, n:

n = 10 + 9 + 10 + 7 + 3 + 4 + 3 = 46

2) Find position, using: $\frac{n+1}{2}$

$\frac{n+1}{2}=\frac{47}{2}$ = 23.5

Median is in the 23.5th position.

3) Find the position by adding frequencies: for this frequency distribution, 23.5th position is 9

Median for this frequency distribution is 9.

<u>Mode</u> is the number or value associated with the highest frequency.

In this frequency distribution, 2 and 9 points happen 10 times. So, mode is 2 and 9.

Mode for this distribution is 2 and 9.

7 0

3 years ago