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likoan [24]
4 years ago
13

________ is a process in which computer software that uses statistical analysis, database technology, and artificial intelligenc

e finds hidden patterns, trends, and connections in data so that business owners can make better marketing decisions and predictions about customer's behavior.
Computers and Technology
1 answer:
QveST [7]4 years ago
6 0

Answer:

Data Mining.

Explanation:

Data Mining is the process in which a computer software uses database technology,artificial intelligence and statistical analysis so that it can find the hidden patterns,connections and trends in the data.To help business owners to make better marketing decisions and predictions about the customer's behavior.

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<span>The statement that P2P networks are most commonly used in home networks is true. 
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1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

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// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

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// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

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// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

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System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

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String test = s2;

while (index != -1) {

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System.out.println("Last location of class in s2 is: " + (ans + 1));

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} // end class StringLab9

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Answer:

Explanation:

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