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andreev551 [17]
3 years ago
13

A typical serial cable has

Computers and Technology
1 answer:
stepan [7]3 years ago
8 0
A typical serial cable it has transfer information from between 2 devices using a serial communication protocol. The form of connectors it depends to particular serial port to be used. 

Hope it helped you!


-Charlie
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write a java program using a do while loop to prompt the user to enter a password. The user should be prompted to enter the pass
Alex787 [66]
We can import Scanner from Java.utils.Scanner to pull in text entered in the console.

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String password = "";
do {
System.out.print("Enter your password: ");
password = sc.nextLine();
if(!password.equals("pals") {
System.out.println(\nIncorrect Password. Try again.");
}
} while(!password.equals("pals");
3 0
3 years ago
The equation of certain traveling waves is y(x.t) = 0.0450 sin(25.12x - 37.68t-0.523) where x and y are in
NNADVOKAT [17]

Answer:

A. 0.0450

B. 4

C. 0.25

D. 37.68

E. 6Hz

F. -0.523

G. 1.5m/s

H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

I. -1.67m/s.

Explanation:

Given the equation:

y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)

Standard wave equation:

y(x, t)=Asin(kx−ωt+ϕ)

a.) Amplitude = 0.0450

b.) Wave number = 1/ λ

λ=2π/k

From the equation k = 25.12

Wavelength(λ ) = 2π/25.12 = 0.25

Wave number (1/0.25) = 4

c.) Wavelength(λ ) = 2π/25.12 = 0.25

d.) Angular frequency(ω)

ωt = 37.68t

ω = 37.68

E.) Frequency (f)

ω = 2πf

f = ω/2π

f = 37.68/6.28

f = 6Hz

f.) Phase angle(ϕ) = -0.523

g.) Wave propagation speed :

ω/k=37.68/25.12=1.5m/s

h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)

(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.

5 0
3 years ago
What is the best Graphics Card you can get in a Gaming Computer? Also what is the RAM do in a Comptuer
saveliy_v [14]

Answer:

For Simple AAA. title games you can get a gtx 1050 ti which can run games decent about 60 fps on med to low settings i my self am running a r7 370 and i play FiveM at 40 fps or gta5 at 60 csgo at 120 fps if you want to go higher go with the best graphics and fps go with something cheap but extreme a RTX 2070 or 2080 and with ram it help the computer run smoother basically imagin what a plate is ram so more plates you have the more food you can store in it untill someone (the computer) uses it all its a quick storage for limited time the more the better usually for gaming a 16gb should be enough

Explanation:

5 0
3 years ago
Device management is the process of managing
faltersainse [42]
Device management is the process of managing the devices in your computer. In your computer you have the so-called device manager, in which all the drivers of your devices are installed. Device Manager allows you to monitor and manage each of its devices. You can also uninstall and update your devices in device manager. And the process of doing it is called device management. It is very simple to do this kind of stuffs as long you are familiar with your devices like mouse, printer, keyboard, etc.
8 0
3 years ago
Write a pyhton program to calculate area of a circle?
marta [7]

Answer:

The code to calculate the area of a circle is:

from math import pi

def circleArea(radius):

 if radius > 0:

   return pi * (radius ** 2)

 else:

   return None

if __name__ == '__main__':

 radius = 5

 print("Radius: {} Area: {}".format(radius,circleArea(radius)))

Explanation:

A detailed explanation of each line of code is given below.

#Define the number pi used to calculate the area

from math import pi

#We define a function that calculates the area of a circle

def circleArea(radius):

#Check if the radius is valid ( radius > 0) since there aren´t negative radius

 if radius > 0:

#Compute the area formula for a circle \pi * radius^{2}

   return pi * (radius ** 2)

 else:

#Return None if the radius is invalid

   return None

#Run the function we´ve defined

if __name__ == '__main__':

#Define a radius

 radius = 5

#Call the function and parse the radius through it, then print the result

 print("Radius: {} Area: {}".format(radius,circleArea(radius)))

8 0
3 years ago
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