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prisoha [69]
3 years ago
8

In the Word 2016 window, where is the Status bar located?

Computers and Technology
1 answer:
klasskru [66]3 years ago
4 0

Answer:

I hope this helps

Explanation:

The answer is B

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Analyze the following code. Number[] numberArray = new Integer[2]; numberArray[0] = new Double(1.5); Question 9 options: A) Sinc
sleet_krkn [62]

Answer:

B) At runtime, new Integer[2] is assigned to numberArray. This makes each element of numberArray an Integer object. So you cannot assign a Double object to it.

Explanation:

The Number class in Java is the superclass for the numbers. Once it is set to the Integer object, the values in <u>numberArray</u> must be all integers, we know that arrays can hold one type of value in Java. Assigning a double value is not allowed in this situation.

7 0
3 years ago
This type of technology does not come with a keyboard or mouse for input
olga55 [171]
Maybe a tablet.... who knows what is this for?

6 0
3 years ago
Read 2 more answers
You have four DCs in your domain. Active Directory appears to be corrupted on one of the DCs, and you suspect a failing hard dri
Softa [21]

Answer:C

Explanation:

5 0
3 years ago
NAND is logically complete. Use only NAND gates to constructgate-level circuits that compute the
Drupady [299]

Answer:

Hi, for this exercise we have two laws to bear in mind:

Morgan's laws

NOT(А).NOT(В) = NOT(A) + NOT (B)

NOT(A) + NOT (B) = NOT(А).NOT(В)

And the table of the Nand

INPUT OUTPUT

A B A NAND B

0 0         1

0 1         1

1 0         1

1 1         0

Let's start!

a.

Input            OUTPUT

A       A     A NAND A

1         1             0

0        0            1

b.

Input            OUTPUT

A       B     (A NAND B ) NAND (A NAND B )

0         0            0

0         1            0

1          0             0

1          1             1

C.

Input            OUTPUT

A       B     (A NAND A ) NAND (B NAND B )

0        0           0

0        1             1

1         0            1

1          1            1

Explanation:

In the first one, we only need one input in this case A and comparing with the truth table we have the not gate

In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.

In the third case we have that the OR is A + B and we know in base of the morgan's law that:

A + B = NOT(NOT(А).NOT(В))

So, we have to negate the two inputs and after make nand with the two inputs negated.

I hope it's help you.

3 0
3 years ago
Write a program that reads two fractions such as 1/2 and 1/4 and computes and stores the sum, the difference, the product and th
Vesnalui [34]

Answer:

1: #include <iostream>

2: using namespace std;

3: int main()

4: {

5: int a,b,c,d;

6: cout<<"n1: ";

7: cin>>a;

8: cout<<"d1: ";

9: cin>>b;

10: cout<<"n2: ";

11: cin>>c;

12: cout<<"d2: ";

13: cin>>d;

14: int top = (a*d)+(b*c);

15: int bottom = b*d;

16: cout<<"Sum: "<<top<<"/"<<bottom<<"\n";

17: top = (a*d)-(b*c);

18: cout<<"Difference: "<<top<<"/"<<bottom<<"\n";

19: top = a*c;

20: cout<<"Product: "<<top<<"/"<<bottom<<"\n";

21: top = a*d;

22: bottom = b*c;

23: cout<<"Quotient: "<<top<<"/"<<bottom<<"\n";

24: return 0;

25: }

Explanation:

The Program is written in C++ programming language

The Program is left numbered

Line 5 was used for variable declaration.

Variables a,b represents the numerator and denominator of the first fraction

While variables c,d represent the numerator and denominator of the second fraction

Line 6 prints "n1" without the quotes which represents the numerator of the first fraction

Line 7 accepts input for the numerator of the first fraction.

Line 8 prints "d1" without the quotes which represents the denominator of the first fraction

Line 9 accepts input for the denominator of the first fraction.

Line 10 prints "n2" without the quotes which represents the numerator of the second fraction

Line 11 accepts input for the numerator of the second fraction.

Line 12 prints "d2" without the quotes which represents the denominator of the second fraction

Line 13 accepts input for the denominator of the second fraction.

Line 14 and 15 calculate the sum of the fractions which is then printed on line 16

Line 17 calculates the difference of the fractions which is then printed on line 18

Line 19 calculates the product of the fractions which is then printed on line 20

Line 21 and 22 calculates the quotient of the fractions which is then printed on line 23

5 0
3 years ago
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