All categories

3 years ago

How does a residential survey help buyers?

2 answers:

3 0

<span>C) buyers are aware of the accurate measurements of the property. A residential survey is also known as a boundary survey and is used to determine the boundaries of a piece of property. It is generally required as part of the process of building new construction on a property to insure that the construction doesn't cross the property line and intrude on someone else's property. With this in mind, only option "C" reflects what a residential survey is.</span>

storchak [24]3 years ago

3 0

Answer:

C. buyers are aware of accurate measurements of the property

Step-by-step explanation:

You might be interested in

The graph shown here is the graph of which of the following rational functions

JulsSmile [24]

Answer:

The answer is 100% B

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

How would I find the are without height and what would the formula be

gregori [183]

The height is 6tan(60)=10.39 then plug that in to trapezoid area formula
(11+6+15)/2*10.39=166.24

8 0

3 years ago

Whats the value of 6 in 3.6?

kenny6666 [7]

6 is in the tenths place.

Written Form: 0.6

6 0

3 years ago

Find the linear approximation of the function f(x, y, z) = x2 + y2 + z2 at (4, 4, 7) and use it to approximate the number 4.022

miss Akunina [59]

Answer:

80.66

Step-by-step explanation:

$L\left( x \right) = f\left( a \right) + f'\left( a \right)\left( {x - a} \right)$

$f(x, y, z) = x^2+y^2+z^2$

Since we have three variables,

$L(x, y,z) = f(a, b,c) + f_x (a, b,c) (x - a) + f_y (a, b,c) (y - b) +f_z(a,b,c)(z-c)$

$f(4, 4, 7) = 4^2+4^2+7^2=81$

$f_x (a, b,c)=2x=2*4=8\\f_y (a, b,c)=2y=2*4=8\\ f_z(a,b,c)=2z=2*7=14$

Therefore:

$L(x, y,z) = 81+ 8(x - 4) + 8 (y - 4) +14(z-7)$

Using the above:

f(4.02, 3.99, 6.97) =81+ 8(4.02 - 4) + 8 (3.99 - 4) +14(6.97-7)=80.66.

The approximation of $4.02^2 + 3.99^2 + 6.97^2$ is 80.66000.

3 0

3 years ago

The average mass of an ant is approximately 3 × 10 − 3 grams. The average mass of a giraffe is approximately 2 × 10 3 kilograms.

Vika [28.1K]

Given that average mass of an ant $= 3 \times 10^{-3}$ grams.

Given that average mass of a giraffe $= 2 \times 10^{3}$ Kilograms.

Now we have to find about how many times more mass does a giraffe have than an ant. Before carring out any comparision, we must make both units equal.

Like convert kilogram into gram or gram into kilogram.

I'm going to convert kilogram into gram using formula

1 Kg = 1000 g

So the average mass of a giraffe $= 2 \times 10^{3} *10^3$ grams.